The pressure, P, of a gas varies inversely with its volume, V. Pressure is measured in units of Pa. Suppose that a particular amount of a gas is initially at a pressure of 104 Pa at a volume of 108 L. If the volume is expanded to 432 L, what will the new pressure be?26 Pa
27 Pa
416 Pa
1728 Pa

Answers

Answer 1
Answer: The answer is 26 Pa.

The ideal gas law can be presented as:
PV = nRT
where
P - pressure of the gas,
V - volume of the gas,
n - amount of substance of gas,
R - gas constant,
T - temperature of the gas.


But, we do not need to know all of the equation members since the right side of the equation is not affected and will remain the same. It is enough the left side of the equation:

P₁V₁ = P₂V₂

It is given:

P₁ = 104 Pa

V₁ = 108 L

V₂.= 432 L


The unknown is P₂ = ?


P₁V₁ = P₂V₂.

104 Pa × 108 L = P₂ × 432 L

11,232 Pa L = P₂ × 432 L

P₂ = 11,232 Pa ÷ 432 

P₂ = 26 Pa


Therefore, the new pressure will be 26 Pa.


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Answers

Answer:

23.2/20

Step-by-step explanation:

i looked it up

Find two numbers with a sum of 20 and a difference of 14.a. 4 and 18
b. –3 and –17
c. 2 and 16
d. 3 and 17

Answers

D is the right option. 3 and 17 make 20. Difference is 17- 3= 14.

What is tan(B)?
13
5
B
12
?
tan(B) =
Enter

Answers

Answer:

tan B = 5/12

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side/ adj side

tan B = 5/12

Between which pair of consecutive integers does square root 21 lie? 10 and 11 5 and 6 20 and 22 4 and 5

Answers

square root of 11. 3 & 4 2. square root of 33. 5 & 6 3. square root of 8. 2 & 3 4. cube root of 220. 6 & 7 5. cube root of -80. 4 & 5 6. fourth root of 20. 2 & 3 7. square root of 300. 17 & 18 8. fifth root of -35. 2 & 3 9. square root of 150. 12 & 13 10. cube root of -312. 6 & 7

Which ordered pairs make both inequalities true? Check all that apply.y < 5x + 2

y > x + 1





(–3, 2)


(–1, 3)



(0, 2)


(1, 2)


(2, –1)


(2, 2)

Answers

Answer:

(1,2) and (2,2) since blue is a solid line

Step-by-step explanation:

To prove if a point satisfies the inequalities,find the point in the point that both inequalities overlap. In the picture, this is colored purple (both pink and blue/purple).


Answer:

(1,2) and (2,2) makes true

Step-by-step explanation:

y < 5x + 2

y >=1/2(x) + 1

(–3, 2)

Plug in the ordered pair (x,y) in each inequality

2 < 5(-3) + 2  -----> false

(–1, 3)

3< 5(-1) + 2 --------> false

(0, 2)

2 < 5(0) + 2  -------> false

(1, 2)

2 < 5(1) + 2 ---------> True

2 >=(1/2)1 + 1 ----------->True

(2, –1)

-1 < 5(2) + 2 ---------> True

-1>= (1/2)(2) + 1 -----------> false

(2, 2)

2 < 5(2) + 2 ---------> True

2>= (1/2)(2) + 1 -----------> True

P is a point on the terminal side of θ in standard position. Find the exact value of the six trigonometric functions for θ.18. P(-3, 2)
19. P(4, -2)
20. P(0, -6)
21. P(-3, -4)

Answers

Answer:

  see below

Step-by-step explanation:

When you're doing a bunch of these, it is helpful to make a table with reminders as to how they're calculated. That table is shown below.

__

In the attached, we have used ...

  r² = x² +y²

  √20 = 2√5

  √36 = 6

  √25 = 5

and 1/(2√5) = √5/10. (The division is outside the radical.)