(n-3)(n-5)what's the equivalent

Answers

Answer 1

Answer: Lets expand the expression using the FOIL method
FOIL=First,Outer,Inner,Last

We'd start by multiplying the first numbers in each parenthesis by eachother:

(n-3)(n-5)
n*n=n²

Now the outer two values...

(n-3)(n-5)
-5n

The inner two values

(n-3)(n-5)
-3n

And the last two values
(n-3)(n-5)
-3*-5=15

Now just put all of the expressions together...

n²-5n-3n+15
simplify
n²-8n+15

Answer=n²-8n+15

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Teesha is in the French club. There are 29 students in the club. The French teacher will pick two students at random to guide visiting students from France. What is the probability that Teesha will not be picked as a guide?

Answers

Probability of event A ( Tesha will not be picked as a guide ) :
P ( A ) = Number of ways it can happen / Total number of outcomes
P ( A ) = (29 - 2) / 29 = 27 / 29 ≈ 0.93
Answer:
The probability that Tesha will not be picked as a guide is 0.93 or 93 %.

The probability that Teesha will not be picked as a guide is 0.931

How to determine the probability?

The given parameters are:

Students = 29

The probability that Teesha will not be picked first is:

P(1) = 28/29

The probability that Teesha will not be picked second is:

P(2) = 27/28

The required probability is:

P = 28/29 * 27/28

Evaluate

P = 0.931

Hence, the probability that Teesha will not be picked as a guide is 0.931

Answers

Answer: 5 times x<-45 the solution is x<-9

Step-by-step explanation:

less than is < and greater than is >

5 x n - 45 is the inequality

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.Write about what additional information you would need to create a two-variable equation for the scenario. What kind of problem could you solve with your equation?

Answers

from the information we have now we could write this equation:

ax+by=z
where
a - number of times she played arcade
x- prize of arcade
b- number of times of Ferris wheel
y- prize of Ferris
z- the whole allowance

so in order to make it a two-variable equasion we need to know the value of three more variables.

If let's say we know a, b, and z we could solve the problem of how much cheaper/more expensive the arcade is than ferris wheel (we could find something like x=2y, for example ( we don't know yet, we need more variables) so we'd know that one game is more expensive than the other.

Sample Response: To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.

The sum of 3 consecutive odd integers is 87.Find the equation used to solve this problem and the three integers.

Answers

the first odd integer is x. The next odd integer will be x+2. and the next is x+4. Then we can say that (x)+(x+2)+(x+4)=87
working that out yields 3x+6=87
and thus 3x=81
and by consequence x=27

and thus our 3 odd integers are 27,29 and 31

Let be y - 2, y and y + 2 the 3 consecutives odd integers;
There sum is 3y, and, in the same time is 87 => y = 87/3 => y = 29 =>
y - 2 = 27; y + 2 = 31;
The 3 integers are : 27, 29, 31.

16. At a certain university the student to teacher ratio is 16:1. If there are 2,000 students enrolled, how many teachers must be employed to maintain this ratio?A. 200
B. 28,000
C. 125
D. 215

Answers

The correct answer is:

C. 125

Explanation:

The student to teacher ratio is 16:1. This can also be written as 16/1.

We can use this to write a proportion and solve for the amount of teachers required. We know that the total number of students is 2000, and the amount of teachers unknown; this gives us the ratio 2000/x. This gives us the proportion

16/1 = 2000/x

Cross multiplying, we have

16(x) = 1(2000)

16x = 2000

Divide both sides by 16:

16x/16 = 2000/16

x = 125

If m < 0 and b > 0, the graph of y = mx + b does not pass through which quadrant?Quadrant I
Quadrant II
Quadrant III
Quadrant IV

Answers

Answer:

Quadrant III

Step-by-step explanation:

The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.

The graphs shown are of the functions:

$y=-2x+1$