For the field trip, there were 31students on each bus.
Given information:
Total number of students on the field trip: 106
13 students rode in cars.
We need to find out how many students were in each bus.
Calculate the number of students who rode in cars.
Number of students in cars = Total students - Number of students in buses
Number of students in cars = 106 - 13
Number of students in cars = 93
Determine the number of students in each bus.
Number of students in each bus = Total students in buses / Number of buses
Number of students in each bus = 93 / 3
Number of students in each bus = 31
So, there were 31 students on each bus.
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Answer: 31
Step-by-step explanation: 106 -13 = 93
93 divided by 106 = 31
x; 0 , 2 , 4 , 6
y; -10 , -1 , 4 , 8
Relation t is not a function. The inverse of relation t is not a function.
Relation t is a function. The inverse of relation t is a function.
Relation t is a function. The inverse of relation t is not a function.
Relation t is not a function. The inverse of relation t is a function.
( I think its a, but not sure ? )
Answer:
Hence, Relation t is a function. The inverse of relation t is a function.
Step-by-step explanation:
We are given the relation as:
x: 0 , 2 , 4 , 6
y: -10 , -1 , 4 , 8
Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).
Hence, the corresponding relation is a function.
Now we have to find whether the inverse of this relation is a function or not.
When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.
Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.
Hence, Relation t is a function. The inverse of relation t is a function.
Answer:
Step-by-step explanation:
Let
We rewrite as an exponential equation to obtain;
We rewrite both sides of the equation as an index number to base 5.
Since the bases are the same, we equate the exponents to obtain;
Divide both sides by 2;
Answer:
C) One!
Step-by-step explanation:
Let’s solve the first equation for y:
6y = 3x - 9 y = (3/6)x - (9/6) y = (1/2)x - (3/2)
Now, we substitute this expression for y into the second equation:
6x - 2y = 14 6x - 2((1/2)x - (3/2)) = 14 6x - x + 3 = 14 5x = 11 x = 11/5
Finally, we substitute this value of x back into either of the original equations to find y:
6y = 3(11/5) - 9 6y = 33/5 - 45/5 6y = -12/5 y = -2/5
Therefore, the solution to the system of equations is C) One.
I hope this helps :D
The improper fraction of is ⇒ 10/3.
The given mixed fraction is
We know that
Every fraction is made up of two parts: the numerator and the denominator. Proper fractions and improper fractions are the two primary forms of fractions in mathematics depending on the numerator and denominator values.
An improper fraction is a type of fraction where the numerator is greater than or equal to the denominator
In order to convert it improper fraction proceed as follow
= (3x3 + 1)/3
= (9+1)/3
= 10/3
Thus improper fraction is 10/3
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