Need help fast! Where does the line y=x-9 cross the y axis? Same with the line y=-2x-3 . Please give me a detailed method as well as an explanation as i need to know this for my end of year exam:)

Answers

Answer 1

Answer: y = x - 9 meets the y-axis at (0,-9) y = -2x - 3 meets the y-axis at (0,-3) This is because for every linear equation, there is a formula corresponding to it as y=mx + c, where (0,c) is where it meets the y-axis. As we assign the value of 0 to x, only c will be left to equal y, being the intercept.

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Adriana's soccer ball is covered with a pattern of pentagons and hexagons in the ratio of 3 to 5. If there are 12 pentagons, how many hexagons are in the pattern?

Vince bought 6 boxes of worms to use as bait while fishing with his friends. If each person uses exactly 3/8 of a box of worms, how many people can share the worms.

Answers

We are given the following information:

each person uses 3/8 a box

there are 6 boxes

Because each box is $(8)/(8)$ , and there are 6 boxes, we know that 1 person is $(3)/(8*6)$ , or $(3)/(48)$ .

In order to find how many people can use the 6 boxes, we can divide it by 3 (for each use):

48 / 3 = 16

Therefore, 16 people can share the worms.

Hope this helps! :)

Plz help what is the missing number 1,4,9,16 what is after 16 plz help me fast thank you

Answers

The answer is 25.

The sequence was following the pattern of squaring numbers that were in chronological order.

1^2=1
2^2=4
3^2=9
4^2=16

So, next number would be 5^2=25.

the answer would be 25

Which equation represents a nonproportional relationship?A. y=3x+0
B. y=-3x
C. y=3x+5
D. y=1/3x

Chose only one!!!!!!

Answers

C. If you have to add on a number it is nonproportional

Su has 5 times as many marbles as Bertha. When Su gives Bertha 10 marbles, they have the same amount. How many marbles did they EACH have at the begining? How many did they EACH have at the end?

Answers

Answer:

Part A)

The number of marbles that Su has at the beginning is $25$

The number of marbles that Bertha has at the beginning is $5$

Part B)

The number of marbles that Su has at the end is $15$

The number of marbles that Bertha has at the end is $15$

Step-by-step explanation:

Let

x------> number of marbles that Su has at the beginning

y------> number of marbles that Bertha has at the beginning

we know that

$x=5y$ ----> equation A

$x-10=y+10$ ----> equation B

substitute equation A in equation B

$(5y)-10=y+10$

$4y=20$

$y=5$

Find the value of x

$x=5(5)=25$

Part A) How many marbles did they EACH have at the begining?

The number of marbles that Su has at the beginning is $25$

The number of marbles that Bertha has at the beginning is $5$

Part B) How many did they EACH have at the end?

$x-10=y+10$

$25-10=5+10$

$15=15$

therefore

The number of marbles that Su has at the end is $15$

The number of marbles that Bertha has at the end is $15$

What is y ? and how do you get it ?

Answers

you first do the opposite of what 4 is. so subtract on both sides. next since y is already being divided by 5 you need to do the opposite which is multiplying. so multiply on both sides and your answer will be y=60

Jacob is solving the equation below using successive approximations.2^x-4=3^-x-2 He started from a graph where he found the solution to be between 1 and 2. Using the lower and upper bounds from the graph, Jacob did the following work for the first iteration. Step 1 Rewrite the equation so that it equals zero on one side. Step 2 Evaluate the rewritten equation at the lower and upper bounds. To find the solution that lies between 1 and 2, set these values as the lower and upper bounds while finding the solution. Step 3 Take the average of the lower and upper bounds. Step 4 Evaluate the rewritten equation at x = . Step 5 Since this value is positive, replace the previous lower bound so that the bounds are now x = and x = 2. Where did Jacob make a mistake, and what was the error?

Answers

The mistake made by Jacob is; D: Jacob made a mistake at step 5. He should have used x=32 as the new upper bound.

How to Solve Successive Approximations?

In Mathematics, successive approximation can be defined as a classical method that is used in Calculus for solving integral equations or initial value problems.

In this question, Jacob started the first iteration of successive approximation by using the lower and upper bounds of the graph. However, we can deduce that Jacob made a mistake instep 5 because he should have used x = 3/2 as the new upper bound.

Read more about Successive Approximations at; brainly.com/question/25219621

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Answer:

For plato users

D. Jacob made a mistake at step 5. He should have used x = 3/2 as the new upper bound.

Step-by-step explanation:

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