Charged objects have a _________ charge. A. net B. moving C. positive D. negative

Answers

Answer 1

Answer: Charged objects have a Net charge.

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A cyclist rides in a circle with speed 8.1 m/s. What is his centripetal acceleration if the circle has a radius of 27 m? A. 3.3 m/s^2 B. 2.4 m/s^2 C. 0.3 m/s^2 D. 1.8 m/s^2

Answers

The answer would be B. 2.4

You're welcome.

Answer:

Answer is B. Just took it!

Explanation:

When an object is at a distance of twice the focal length from a concave lens, the image produced is virtual and smaller than the object. What happens to the image if the object is shifted closer to the lens to a point one focal length away from it?The image produced is virtual and enlarged.
The image produced is virtual and smaller than the object.
The image produced is real and enlarged.
The image produced is real and smaller than the object.
The image produced is virtual and of the same size as the object.

Answers

Answer:

The image produced is virtual and smaller than the object.

Explanation:

For concave lens we know that

$(1)/(d_i) + (1)/(d_o) = (1)/(f)$

here we have

$(1)/(d_i) + (1)/(2f) = -(1)/(f)$

$(1)/(d_i) = - (3)/(2f)$

$d_i = -(2f)/(3)$

Magnification will be given as

$M = (d_i)/(d_o)$

$M = -2/3$

so image will be virtual and formed behind the lens

Now the object position is shifted to new position at distance of focal length

now again we will have

here we have

$(1)/(d_i) + (1)/(f) = -(1)/(f)$

$(1)/(d_i) = - (2)/(f)$

$d_i = -(f)/(2)$

Magnification will be given as

$M = (d_i)/(d_o)$

$M = -1/2$

So again we will have virtual image with magnification 1/2

so here size of image is less than object size by factor of 1/2 and it is virtual

The right answer for the question that is being asked and shown above is that: "The image produced is virtual and of the same size as the object." the image if the object is shifted closer to the lens to a point one focal length away from it is that The image produced is virtual and of the same size as the object.

An event occurs in system K’ at x’ = 2 m, y’ = 3.5 m, z’= 3.5 m, and t’= 0. System K’ and K have their axes coincident at t = t’= 0, and system K’ travels along the x axis of system K with a speed 0.8c. What are the coordinates of the event in system K?

Answers

The coordinates of the event in system K can be found using the Lorentz transformation equations, and they are (10/3 m, 3.5 m, 3.5 m, 8/3 m/c).

The Lorentz transformation equations relate the coordinates of an event in one reference frame to the coordinates of the same event in another reference frame that is moving with a constant velocity relative to the first reference frame.

The equations are as follows:

x = γ(x' + vt')

y = y'

z = z'

t = γ(t' + vx'/c^2)

Where γ is the Lorentz factor, which is given by:

γ = 1/√(1-v^2/c^2)

In this case, v = 0.8c, so γ = 1/√(1-(0.8c)^2/c^2) = 5/3.

Plugging in the values for x', y', z', t', v, and γ into the Lorentz transformation equations, we get:

x = (5/3)(2 m + (0.8c)(0)) = 10/3 m

y = 3.5 m

z = 3.5 m

t = (5/3)(0 + (0.8c)(2 m)/c^2) = 8/3 m/c

Therefore, the coordinates of the event in system K are (10/3 m, 3.5 m, 3.5 m, 8/3 m/c).

To know more about Lorentz transformation equations, refer here:

brainly.com/question/29655824#

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An electric refrigerator rated 400 W operates 8 hours a day. Find the energy used per day in KWh.

Answers

400 watts = 0.4 kw

(0.4 kw) x (8 hours) = 3.2 kw-hours

_______ was the first person to propose the idea of moving continents as a scientific hypothesis. A. Antonio Snider-Pelligrini
B. Alfred Wegener
C. Charles Richter
D. Abraham Ortelius

Answers

B.Alfred Wegener was the first person to propose the idea of moving continents as a scientific hypothesis.

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A kite is 100m above the ground. If there are 200m of string out, what is the angle between the string and the horizontal? (Assume that the string is perfectly straight.)

Answers

Answer:

the answer is 30°

Explanation:

due to:

sin law of sines

$(sin 90)/(200) =(sin\beta )/(100)\narcsin(100(sin90)/(200) )= 30°$

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