Answer:
No, Isiah is not correct. The GCF of the coefficients is 1, and there are no common variables among all three terms of the polynomial. 5b4 is a factor of -25a2b5 and -35b4, but not a3. Additionally, a2 is a factor of a3 and -25a2b5, but not -35b4.
Answer:
Answer D
Step-by-step explanation:
The solution to the inequality 2x³ – 3x² – 14x ≥ 0, as indicated by the graph provided, is given by the intervals of x where the function is increasing. Therefore, the solution is comprised of the intervals [-2, -1] and [3.5, ∞].
The solution to 2x³ – 3x² ≥ 14x can be found by solving the inequality. First, let's rearrange the inequality to: 2x³ – 3x² – 14x ≥ 0. This equation represents where the function is positive (above the x-axis) on the graph. Therefore, we must identify the intervals of x where the function increases or decreases.
Based on the description of the graph, the function increases in the intervals (-2, -1) and (3.5, ∞) and decreases in the interval (-1, 3.5). So, the solution to the inequality would be the union of the intervals where the function increases: [-2, -1] U [3.5, ∞].
#SPJ3
2 3/12+3\? =2 5/8
2 3/12 +3/x = 2 5/8
simplify to
9x+12/4x = 21/8
Cross multiply
(9x+12)/(4x) = 21/8
(9x+12)*(8) = 21*4x
72x+96 = 84x
Subtract 84 x from both side
72x+96 - 84x = 84x -84x
-12x+96 = 0
Subtract 96 from both sides
-12x+96-96 = 0-96
-12x = -96
Divide both sides by 12
-12x/-12 = -96/-12
x = 8
The missing value is 8
f:d->R
f(x)=x at power2/x-1
Answer:
x=16
Step-by-step explanation: