Janna jumped 156 inches in the long jum competition how many feet did Janna jump

Answers

Answer 1
Answer: 1 foot=12 inches
Divide 12 from 156.
156÷12=13

Janna jumped 13 feet in the long jump competition, which is actually really good!

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How do you compute two thirds of 6 ounces


what is two thirds of 6 ounces

Answers

(2/3) times (6) = 12/3 = 4
the answer to your question is two thirds of 6 ounces is 4

A conical tent is to accommodate 77 persons. Each person must have 16m³ of air to breathe. Given the radius of the tent as 7m find the height of the tent and also its curved surface area.

Answers

Answer:

Total air in the tent =77×16=1232 m 3 (which is the total volume of tent) Since the tent is conical we will use some formula of cone: Volume= 31πr 2h ; Curved surface area=πrl l= slant height & r=7m Volume = 31πr 2h= 31π(7 2)h= 31 7227 2h= 3154h And we eknow that total volume is 1232m 3 So, 1232= 3154h h= 1541232×3=24m

Step-by-step explanation:

Final answer:

To solve this problem, we need to use the volume formula of a cone and equate it to the total volume of air needed by the 77 persons. Once we solve for the height, we can then determine the curved surface area of the cone using the radius and height.

Explanation:

This mathematics problem can be solved using the formula for the volume of a cone, which is given by V = 1/3 * π * r² * h where “r” stands for the radius of the base of the cone, “h” corresponds to the height, and “π” is a constant that roughly equals to 3.14. To accommodate 77 persons, with each person needing 16 m³ of air to breathe, the total volume necessary would be 77 * 16 = 1232 m³. Setting this equal to the volume of the cone formula and plugging in the given radius (r = 7 m), we solve for the height. Simultaneously, the curved surface area of a cone is given by A = π * r * l = π * r * sqrt((r²)+(h²)). We can evaluate both the height of the tent and its curved surface area applying these equations.

Learn more about Volume and Surface Area of Cone here:

brainly.com/question/33666909

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One leg of an isosceles right triangle measures 5 inches. Rounded to the nearest tenth, what is the approximate length of the hypotenuse?a.) 2.5 inches b.) 5.0 inches c.) 7.1 inches d.) 9.8 inches

Answers

c right there i think

The answer is C. 7.1 inches

John wants to fence in a portion of his back yard. The dimensions of the area is 12 1/2 yards long and 5 1/2 yards wide. How many feet of fencing does john need to buy to enclose this area?

Answers

25 and 11... so, ultimately, it would be 36 feet of fencing that he needs.

           ---------------------------------
           |            5 1/2 yards         |
           |                                       |
           |                                       |
           |                                       |
           |                                       |    12 1/2 yards
           |                                       |
           |                                       |
           |                                       |
           ____________________
                       5 1/2 yards

The surface of this shape is called a rectangle.
Opposing sides of the rectangle are of equal length .
To fully fenced backyard you have to put a fence line the sides of the rectangle. The length of the fence will be equaled total sides of the rectangle.
the sum of the sides of the rectangle = perimeter of a rectangle
 2a   +   2b                                          = P

a = 12 1/2 yards
b =  5 1/2 yards

2* 12 1/2 yards + 2* 5 1/2 yards = 25yards + 11 yards = 36 yards

Answer : 36 uards

All of them are right except for number 1 like the “1 units up is wrong and the answer for that one is also not 5 or 6, I already tried so. Please I can’t get it wrong again!

Answers

Answer:

it is 5 to figure 9 you move 8 units and 2 units

Is 6/8 greater than 6/7

Answers

6/7 is greater then 6/8.

I hope this helped! :D :) :P :3