A Middle Eastern restaurant recorded the number of times 2 dinner appetizers, hummus and baba ghanoush, were ordered every day for 1 month. The restaurant calculated the mean number of times each appetizer was ordered and the MAD (mean absolute deviation) for each appetizer. | Appetizer | Orders sold |
Mean | MAD
---------------------------
Hummus 24.3 | 3.1
Baba ghanoush 11.5 | 2.9






Which statement best describes the overlap in the distribution of the two data sets?

A.
The overlap is high because both means are greater than either MAD.

B.
The overlap is high because the sum of the means is large compared to the MAD.

C.
The overlap is low because the difference in the MADs is small.

D.
The overlap is low because the difference in the means is large compared to either MAD.

Answers

Answer 1
Answer: The best answer to the question that is being presented above would be letter c. As indicated with the given data above, the overlap is low because the difference in the MADs is small. It shows only a .2 difference between the MADs given above in the problem.

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Simplify the Following:

3√3 (5 + 3√2 )

Answers

Answer: 15√3 + 9√6

Step-by-step explanation:

3√3 (5 + 3√2 )

= 3√3 x 5 + 3√3 x 3√2 (Apply the distributive rule. a(b+c) = ab+ac)

= 15√3 + 9√6 (Multiply the radicands, then multiply the constants. No mixing)

What is the simplified form of the quantity 4 z squared minus 4z minus 15 over the quantity 2 z squared plus z minus 15? (6 points)

Answers

Answer: The simplified form of the given equation is (2z+3)/(z+3)

Step-by-step explanation:

From the given information, the numerator of the given fraction is: 4z^2-4z-15

and denominator of the given fraction is 2z^2+z-15

The fraction becomes:

(4z^2-4z-15)/(2z^2+z-15)

Applying middle term factorization in the numerator and denominator term, we get:

= (4z^2-10z+6z-15)/(2z^2+6z-5z-15)

= (2z(2z-5)+3(2z-5))/(2z(z+3)-5(z+3))

= ((2z+3)(2z-5))/((2z-5)(z+3))

Cancelling (2z-5) factor from numerator an denominator, we get:

= (2z+3)/(z+3)

The above fraction is the simplified form of the equation formed in the question.

First you simplify it down to (2z+3)(2z-5)/(2z-5)(z+3)
Both of the brackets containing (2z-5) can now be cancelled out leaving you with a final answer of (2z+3)/(z+3)

Find the surface area of the following figures 16 ft 13 ft 12ft 19ftPlease help me solve number 3! And if i got #2 incorrect, please help me fix that one too.

Answers

Answer:

1192 ft²

Step-by-step explanation:

Figure 3 is a trapezoidal prism.

The total surface area of a trapezoidal prism is made up of 2 congruent trapezoid bases and 4 rectangular faces connecting the bases.

The formula for the area of a trapezoid is:

\boxed{S.A.=(1)/(2)(a+b)h}

where a and b are the bases, and h is the height.

From observation of the given diagram, the bases are 16 ft and 19 ft, and the height is 12 ft. Therefore, the area of each trapezoid base is:

\begin{aligned}\textsf{Area of trapezoid base}&=(1)/(2)(16+19)\cdot 12\n\n&=(1)/(2)(35)\cdot 12\n\n&=17.5\cdot 12\n\n&=210\; \sf ft^2\end{aligned}

To calculate the areas of all the rectangular faces, we first need to calculate the slant (s) of the trapezoid base by using the Pythagoras Theorem:

\begin{aligned}s^2&=(19-16)^2+12^2\ns^2&=3^2+12^2\ns^2&=9+144\ns^2&=153\ns&=√(153)\end{aligned}

The area of a rectangle is the product of its width and length.

Therefore, the sum of the areas of the rectangular faces is:

\begin{aligned}\textsf{Area of rectangular faces}&=16\cdot13+12\cdot13+19\cdot13+√(153)\cdot13\n&=208+156+247+13√(153)\n&=771.801119...\n&=772\; \sf ft^2\;(nearest\;foot)\end{aligned}

To find the total surface area of the given trapezoidal prism, sum the area of the two trapezoid bases and the area of the rectangular faces:

\begin{aligned}\textsf{Total S.A.}&=2 \cdot 210+772\n&=420+772\n&=1192\; \sf ft^2\end{aligned}

Therefore, the total surface area of the given trapezoidal prism is 1192 ft², rounded to the nearest foot.

What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405?11,097
11,508
11,919
12,330

Answers

Given:
58 - term 
first term : 6
last term : 405

Sum = n * (a+l)/2
Sum = 58 * (6 + 405)/2
Sum = 58 * 411/2
Sum = 58 * 205.5
Sum = 11,919

Answer:

11,919

Step-by-step explanation:

took the test

Helpppppppppp aasapppp

Answers

Answer:

2

Step-by-step explanation:

Convert mixed fraction to improper fraction

-2(2)/(3)=-(8)/(3)\n\n\n-1(1)/(3)=-(4)/(3)

-2(2)/(3) ÷ -1(1)/(3) =(-8)/(3) ÷ -(4)/(3)

                  =-(8)/(3)*-(3)/(4)\n\n\n=2 *1 \n\n= 2

Answer:

2

Step-by-step explanation:

Simplify the following:

(-(2 + 2/3))/(-(1 + 1/3))

(-(2 + 2/3))/(-(1 + 1/3)) = (-1)/(-1)×(2 + 2/3)/(1 + 1/3) = (2 + 2/3)/(1 + 1/3):

(2 + 2/3)/(1 + 1/3)

Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:

(2 + 2/3)/(3/3 + 1/3)

3/3 + 1/3 = (3 + 1)/3:

(2 + 2/3)/((3 + 1)/3)

3 + 1 = 4:

(2 + 2/3)/(4/3)

Put 2 + 2/3 over the common denominator 3. 2 + 2/3 = (3×2)/3 + 2/3:

((3×2)/3 + 2/3)/(4/3)

3×2 = 6:

(6/3 + 2/3)/(4/3)

6/3 + 2/3 = (6 + 2)/3:

((6 + 2)/3)/(4/3)

6 + 2 = 8:

(8/3)/(4/3)

Multiply the numerator by the reciprocal of the denominator, (8/3)/(4/3) = 8/3×3/4:

(8×3)/(3×4)

(8×3)/(3×4) = 3/3×8/4 = 8/4:

8/4

The gcd of 8 and 4 is 4, so 8/4 = (4×2)/(4×1) = 4/4×2 = 2:

Answer: 2

The combined area of two squares is 45 square centimeters. Each side of one square is twice as long as a side of the other square. What is the length of each side of the larger square?

Answers

a - side of the square
a₁ - arm the small square
a
₂ - larger side of the square
2a
= a₂  we put into the equation 2
(a₁)² + (a₂)² = 45cm²

2a₁ = a₂
(a₁)² + (2a₁)² = 45cm²
(a₁)² + 4(a₁)² = 45cm²
5(a₁)² = 45cm²
(a₁)² = 9cm²
a₁ = √(9cm²) = 3cm
a₂ = 2a₁ = 2*3cm = 6cm
A₁ = (a₁)² = (3cm)² = 9cm²
A₂ = (a₂)² = (6cm)² = 36cm²
A₁ + A₂ = 9cm² + 36cm² = 45cm²