We have that When a carbon atom losses a proton Boron element would be formed.
Boron element
From the question we are told
Is a carbon atom spontaneously lost a proton what element would be formed
Generally
Carbon as an element has an atomic number of 6
Therefore
When a carbon atom losses a proton Boron element would be formed.
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Answer: Protons carry a positive electrical charge and they alone determine the charge of the nucleus. Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. So, adding or removing protons from the nucleus changes what element that atom is!
Explanation: For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium. (Actually, a few neutrons have to be added as well to make the new nucleus stable, but the end result is still helium.) Keep in mind that atoms, by definition, are electrically neutral and always contain the same number of protons and electrons.
B a nonmetal bonds with another nonmetal
C a metal bonds with a nonmetal
D three nonmetals bond together
Answer:
Xe = 0.431 mole
Kr = 0.569 mole
Explanation:
We are asked to calculate the mole fraction of each gas
Let's start from, what is mole fraction?
Mole fraction is the ratio of the number of moles of a substance to the total number of moles of all substance present in the mixture
In this question, we are provided with
Xe - 43.6g
Let's find the number of mole
n = m/Mm
n - number of mole
m - number of mass in grams
Mm - number of molar mass
The molar mass of Xe according to the periodic table is 131.293u
m - is given to be 43.6g
n = 43.6g / 131.293g/mol
n = 0.332mole
Secondly,
Kr - 36.8g
The molar mass of Kr is 83.798
m = 36.8
Using the same formula we used above to find mole
n = 36.8g / 83.798g/mol
n = 0.439mole
Let's calculate the total number of mole in the mixture
Total number of mole = 0.332 + 0.439
= 0.771 mole
To find each mole of each gas in the mixture, using this formula
Mole fraction of a gas = mole of gas A / total mole of the mixture
In Xe = 0.332 / 0.771
= 0.431 mole of Xe in the mixture of the gas
For Kr = 0.439 / 0.771
= 0.569 mole of Kr in the total mixture
differentiate benzene and cyclohexane
Answer:
1981.38L
Explanation:
P=29.8atm;
T=273+99.9=372.9⁰K
V=90.82L
P₀=1atm
T₀=273⁰K
V₀-?
PV/T=P₀V₀/T₀
V₀=PVT₀/P₀T=