B.Two pairs of corresponding sides and one pair of corresponding angles
C.Two pairs of corresponding angles
D.Two pairs of corresponding sides
Answer:
Option C is correct.
Two pairs of corresponding angles
Step-by-step explanation:
Given triangle XYZ has been dilated to form triangle LMN.
Dilation states that it is a transformation that produces an image that is the same shape as the original, but of a different size.
therefore, the triangle XYZ by a dilation is similar to triangle LMN
Similar figures have the
*same shape
*equal corresponding angle measures, and
*have proportional sides.
Therefore, the information which is needed to prove that two given triangles are similar is two pairs of corresponding angles
Two pairs of corresponding angles
The total cost, in pounds, for X jumpers at £15 each and Y shirts at £12 each can be written as the mathematical expression: 15X + 12Y, where X and Y are the quantities of jumpers and shirts respectively.
To write an expression for the total cost of X jumpers at £15 each and Y shirts at £12 each in pounds, you need to multiply the cost per item by the quantity of each items and then add these two products together.
So, the total cost can be given as:
where
In this expression, '15X' stands for the total cost of the jumpers and '12Y' stands for the total cost of the shirts.
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also elements of F.
Greetings from Brasil...
G = {4; 8; 12; 16; 20; 24; 28; 32; 36; 40; 44; 48; 52; 56; 60; 64; 68; 72; 76; 80; 84; 88; 92; 96; 100; 104; ...}
F = {1; 4; 9; 16; 25; 36; 49; 64; 81; 100; ...}
So, according to the statement, it is desired:
G ∩ F - the intersection between the 2 sets, that is, which numbers are present simultaneously in the 2 sets....
Looking at the sets we conclude that
OBS: note that in truth G are the multiples of 4
The first five elements of set H, which include positive integers divisible by 4 that are also perfect squares, are 4, 16, 36, 64, and 100.
The two sets mentioned in the problem are Set G, which contains positive integers divisible by 4, and Set F, which contains perfect squares. The intersection of these two sets is Set H. To find the elements of Set H, we look for numbers that are both divisible by 4 and perfect squares. The first five such numbers are 4, 16, 36, 64, and 100. For example, 16 is both a multiple of 4 and a perfect square because it can be expressed as 4*4 and is the square of 4. Similarly, 36 fits both criteria because it can be expressed as 4*9 and is the square of 6. We continue this pattern to identify the first five elements of Set H.
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B. 28
C. 24
D. 20