Answer:
Step-by-step explanation:
First we need to find the point that the perpendicular line goes through on this line segment. The problem says it's a perpendicular bisector, which means it goes through the middle of the line, which means the point it goes through is halfway between (4, 4) and (-8, 8). This point would be (-2, 6).
Next, we need to find the slope of the perpendicular line. We know that if the slope of the line segment we're given is , then the slope of the line perpendicular to this line segment is .
The slope of the line segment can be found by the following:
This means that the slope of the perpendicular line is 3.
The equation of a line is , were is the slope and is the Y-intercept.
We know the slope, we so we just need to determine the Y-intercept. To do so, we can plug in a point that we know the line goes through, (-2, 6), and solve for :
Finally, the equation of the line is
Answer:
The initial value of the function is 5
Step-by-step explanation:
we know that
The initial value of the function, is the value of the function when the value of x is equal to zero (the y-intercept)
In this problem
Observing the graph
The y-intercept is the point (05)
therefore
The value of the function for x equal to zero is 5
A. In a flowering plant, the embryo is in seeds found in the flower, and in non-flowering plants, the embryo is in seeds found in the cone.
B. In a non-flowering plant, the embryo is in spores found in the stem, and in a flowering plant, the embryo is in seeds found in the flower.
C. In a non-flowering plant, the embryo is in seeds in the leaves, and in a flowering plant, the embryo is in seeds found in the spores.
D. In a flowering plant, the embryo is in spores found in the flower, and in a non-flowering plant, the embryo is in seeds found in the spores.
Answer:
I have not read it but
Step-by-step explanation:
i think the A is right answer.
Answer:
DB = CA (Proved)
Step-by-step explanation:
Statement 1.
∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2
Reason 1.
Given
Statement 2.
Between Δ DBM and Δ CAM,
(i) DM = CM,
(ii) ∠D = ∠C and
(iii) ∠DMB = ∠CMA
Reason 2.
(i) given
(ii) given and
(iii) ∠ DMB = ∠1 + ∠AMB and ∠CMA = ∠2 + ∠AMB
Since ∠1 = ∠2, so, ∠DMB = ∠CMA.
Statement 3.
Δ DBM ≅ Δ CAM
Reason 3.
By angle-side-angle rule.
Statement 4.
DB = CA
Reason 4.
Corresponding sides of two congruent triangles. (Answer)
sides 3.3 cm long