Convert 47.2 g CO= ______ molecules CO

Answers

Answer 1
Answer:

Answer:

1.01 x 10^24 molecules

Explanation: This problem is solved by remembering Avogadro's number and since we have the mass of CO, we can easily calulate the number of moles.

Molecular Weight CO : 28.01 g/mol

47.2 g *  1mol / 28.01 g = 1.68 mol

Now 1 mol of CO is 6.022 x 10^23 molecules ( Avogadro's Number) then

1.68 mol CO * 6.022 x  10^23 =  1.01 x 10^24 molecules


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When a warm air mass is caught between two cooler air masses and the thicker cold air masses move underneath the thinner warm air mass and push it upward is what type of weather front?

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An atomic nucleus is composed ofA)protons.
B)protons and neutrons.
C)protons and electrons.
D)protons, neutrons, and electrons.

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Answer:

B)protons and neutrons.

5. Enzymes and acidic juices in the stomach, whichbreak proteins down into smaller molecules, is known

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Is bro2 polar or nonpolar​

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Which type of rock has sand, minerals,and shells

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155.4 grams of carbon tetrachloride to atoms

Answers

30.41 × 10²³ atoms

Explanation:

First we calculate the number of moles of carbon tetrachloride (CCl₄):

number of moles = mass / molar weight

number of moles of CCl₄ = 155.4 / 153.8 = 1.01 moles

Now to find the number of atoms in 155.4 grams of carbon tetrachloride we use Avogadro's number:

if in         1 mole of CCl₄ there are 5 × 6.022 × 10²³ atoms

then in   1.01 moles of CCl₄ there are X atoms

X = (1.01 × 5 × 6.022 × 10²³) / 1

X = 30.41 × 10²³ atoms

Learn more about:

Avogadro's number

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