Answer:
1.01 x 10^24 molecules
Explanation: This problem is solved by remembering Avogadro's number and since we have the mass of CO, we can easily calulate the number of moles.
Molecular Weight CO : 28.01 g/mol
47.2 g * 1mol / 28.01 g = 1.68 mol
Now 1 mol of CO is 6.022 x 10^23 molecules ( Avogadro's Number) then
1.68 mol CO * 6.022 x 10^23 = 1.01 x 10^24 molecules
B)protons and neutrons.
C)protons and electrons.
D)protons, neutrons, and electrons.
Answer:
B)protons and neutrons.
That would be sedimentary rock
30.41 × 10²³ atoms
Explanation:
First we calculate the number of moles of carbon tetrachloride (CCl₄):
number of moles = mass / molar weight
number of moles of CCl₄ = 155.4 / 153.8 = 1.01 moles
Now to find the number of atoms in 155.4 grams of carbon tetrachloride we use Avogadro's number:
if in 1 mole of CCl₄ there are 5 × 6.022 × 10²³ atoms
then in 1.01 moles of CCl₄ there are X atoms
X = (1.01 × 5 × 6.022 × 10²³) / 1
X = 30.41 × 10²³ atoms
Learn more about:
Avogadro's number
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