f(x) = (x + 3)2 − 6
f(x) = (x + 6)2 + 3
f(x) = (x + 6)2 − 6
By completing the square, the second orderpolynomial in vertexform f(x) = (x + 3)² - 6 is equivalent to the polynomial in standardform f(x) = x² + 6 · x + 3. (Correct choice: B)
In this question we must change the form of the second orderpolynomial from standardform into vertexform. A common method consists in completing the square, that is, to transform part of the polynomial into a perfect squaretrinomial. Now we proceed to find the vertexform of the expression:
1) x² + 6 · x + 3 Given
2) x² + 6 · x + 9 - 6 Modulative property/Existence of additive inverse/Definition of addition
3) (x + 3)² - 6 Associative property/Perfect square trinomial/Result
By completing the square, the second orderpolynomial in vertexform f(x) = (x + 3)² - 6 is equivalent to the polynomial in standardform f(x) = x² + 6 · x + 3. (Correct choice: B)
To learn more on second order polynomials in vertex form: brainly.com/question/20333425
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Answer:
B. f(x) = (x + 3)2 − 6
Step-by-step explanation:
I just did this for "completing the square". Hope this helped!
B. The cost of a bunch of grapes compared with its weight
C. The height of a bird over time
D. The number of tickets sold compared with the number of minutes before a football game
Answer:
Step-by-step explanation:
We'll start with the first term: . The square root of 49 is 7, so this term simplifies to , which is 49.
Now let's simplify the second term: . The square root of a negative number is not defined in the real number system, so we need to express it as a complex number. The square root of -16 can be written as 4i, where 'i' represents the imaginary unit (√(-1)). Therefore, √(-16) = 4i.
Now we can rewrite the expression with the simplified terms:
So, the simplified expression, written as a complex number, is 49 - 4i.
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