At the zoo there were 5 times as many tigers as lion Tom counted a total of 54 tigers and lions how many.tigers were there?

Answer:

nearest integer 27 by 4

Answer:

126 degree

Step-by-step explanation:

use alternate angles and linear pair

Answer: D, the fourth option.

Step-by-step explanation:

Answer:

If you play this game once (and it costs you nothing to play), the expected amount of money you will win is:

$8.

Step-by-step explanation:

a) Data and Calculations:

The probability for the result to be 1 or 2 = 33.33% (100/6 * 2)

The probability for the result to be 3, 4, or 5 = 50% (100/6 * 3)

The probability for the result to be 6 = 16.67% (100/6 * 1)

Data Table:

Event                              Probability       Value Won

The result is 1 or 2           33.33%              $0

The result is 3, 4 or 5     50.00%              $4.00

The result is 6                 16.67%              $36.00

Expected Value:

Event                              Probability          Value              Expected Value

The result is 1 or 2           33.33%              $0                $0 ($0 * 33.33%)

The result is 3, 4 or 5     50.00%              $4.00           $2.00 ($4 * 50%)

The result is 6                 16.67%              $36.00          $6.00 ($36 * 16.67%)

Total expected amount of money  =                             $8.00

Final answer:

The expected win from playing the game once is $8. This is calculated by finding the expected value of the winnings, which is the sum of the possible outcomes each multiplied by their probabilities.

Explanation:

This question is asking about the expected amount of money one can win in a game involving a six-sided die. The concept of 'expectation' in probability and statistics refers to the average result of an experiment if it were repeated many times.

In our game, the possible outcomes when you roll the die are $0 (when we roll 1 or 2), $4 (when we roll 3, 4 or 5), and $36 (when we roll a 6). Now, to calculate the expected value, or the expected amount of money one would win in this game, we multiply each possible outcome by their probability and sum them up.

We have a 1/3 chance of winning $0, a 1/2 chance of winning $4, and a 1/6 chance of winning $36. Therefore, the expected value of winnings would be:

(1/3 * $0) + (1/2 * $4) + (1/6 * $36) = $0 + $2 + $6 = $8

Therefore, if you play this game once, the expected amount of money you will win is $8.

Learn more about Expected Value here:

brainly.com/question/37190983

#SPJ11

Answer:

Mean= $21.5067

Median = $15.8

Standard deviation= $19.02

Coefficient of skewness= $0.8991

Step-by-step explanation:

Mean =( $4.0 +$6.0 +$7.4+ $10.6 +$12.5+ $13.6+ $15.4+ $15.8 +$16.8

+$17.4+ $19.1 +$22.3+ $37.1 +$43.2 +$81.4)/15

Mean =$ 322.6/15

Mean= $21.5067

Median= middle number

Median = $15.8

Variance=( ($4.0-.$21.5)²+( $6.0. -.$21.5)²+( $7.4 -.$21.5)²+( $10.6 -.$21.5)²+( $12.5 -.$21.5)²+( $13.6. -.$21.5)²+ ($15.4 -.$21.5)²+( $15.8 -.$21.5)²+ ( $16.8 -.$21.5)²+ ($17.4-.$21.5)² +($19.1 -.$21.5)²+ ($22.3 -.$21.5)²+ ($37.1 -.$21.5)²+ ($43.2-.$21.5)²+( $81.4-.$21.5)²)/15

Variance=$ 5424.79/15

Variance=$ 361.65

Standard deviation= √ variance

Standard deviation= √361.65

Standard deviation= $19.02

Coefficient of skewness

=3( mean-median)/standard deviation

= 3(21.5-15.8)/19.02

= 3(5.7)/19.02

= 17.1/19.02

Coefficient of skewness= 0.8991