A particle moving along a line has position s(t) = t^4 − 20t^2 m at time t seconds. Determine: (a)- At which times does the particle pass through the origin? (b)- At which times is the particle instantaneously motionless.
Answers
The particle passes through the origin at t = 0 and t = ±√20. The particle is instantaneously motionless at t = 0 and t = ±√10.
(a) To determine the times at which the particle passes through the origin, we need to find when the position function equals zero. So, we set s(t) = 0 and solve for t.
t4 - 20t2 = 0
Factoring out a t2, we get:
t2(t2 - 20) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial position), and t = ±√20 (approximately t = ±4.47).
(b) To determine when the particle is instantaneously motionless, we need to find when the velocity of the particle is equal to zero. The velocity function of the particle is the derivative of the position function. So, we differentiate s(t) with respect to t to find the velocity function.
v(t) = s'(t) = 4t³ -40t
Setting v(t) = 0, we have:
4t³ -40t = 0
Factoring out a 4t, we get:
4t(t² - 10) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial velocity), and t = ±√10 (approximately t = ±3.16).
Learn more about Particle Motion
#SPJ2
Final answer:
The particle passes through the origin at t = 0 and t = √20 seconds. The particle is instantaneously motionless at t = 0 and t = ±√10 seconds.
Explanation:
The position of the particle at time t is given by the equation s(t) = t4 - 20t2. To determine the times when the particle passes through the origin, we set s(t) equal to zero and solve for t. This gives us the quadratic equation t4 - 20t2 = 0, which can be factored as t2(t2 - 20) = 0. The solutions to this equation are t = 0 and t = ±√20. Since t cannot be negative in this scenario, the particle passes through the origin at t = 0 and t = √20 seconds.
To determine the times when the particle is instantaneously motionless, we need to find the times when the velocity of the particle is equal to zero. The velocity of the particle can be found by taking the derivative of the position function with respect to time, v(t) = 4t3 - 40t. Setting this equation equal to zero and solving for t gives us the cubic equation 4t3 - 40t = 0. This equation can be factored as 4t(t2 - 10) = 0. The solutions to this equation are t = 0 and t = ±√10. Therefore, the particle is instantaneously motionless at t = 0 and t = ±√10 seconds.
Learn more about Particle motion here:
#SPJ5
Related Questions
Find the six rational numbers between -4 and 5/4
Compare the subtraction problems (6/8-5/8=1/8) and (6/9-7/9=-1/9) why is the answer to the first problem positive nad the answer to the second problem negative select all that apply
Find the volume of a cylinder with radius of 4 meters and height of 12 meters?
The bases on a softball field are square what is the area of each base if the width is 15 in and the length is 15 inches
Answers
4x + 32
172°
Your answer
Answers
Answer:
x=35
Step-by-step explanation:
Because the 2 lines are parallel u kno 172=4x+32
from there: 172-32=4x or 140=4x, and then 140/4=x
Final answer:
To solve for 'x' in the equation 4x + 32 = 172, we isolate 'x' by first subtracting 32 from both sides of the equation. This gives us 4x = 140. Then, solving for 'x', we divide both sides by 4, resulting in 'x' equal to 35.
Explanation:
To find the value of x, we need to use the process of algebraic simplification. In the equation provided, isolate x by subtracting 32 from both sides of the equation:
4x + 32 = 172
4x = 172 - 32
4x = 140
Next, solve for x by dividing both sides of the equation by 4:
x = 140 / 4
x = 35
Therefore, the value of x in the equation is 35.
Learn more about Algebra here:
#SPJ2
Answers
Hope this helps!
Answers
Answer and Step-by-step explanation:
Let
Number of chocolate chip cookies = x
Number of oatmeal brownie cookies = y
Bake chocolate chip cookies up to 20 dozen = x≤ 20
Bake oatmeal brownies up to 40 dozen= y≤40
Total cookies = x + y ≤ 50
Number of oatmeal brownie will be no more than three times the number of chocolate chip= y≤3x
From the inequality:
X + y=50
y = 3x
By putting the value of y, we get
x + 3x = 50
4x = 50
X = 12.5
By putting the value of x=12.5 in equation y = 3x, we get
Y = 3(12.5)
= 37.5
Craig should make 12.5 dozen chocolate chip and 37.5 dozen oatmeal brownies in order to make more money.
exam, which statement about the graph is true?
Answers
*a clearer picture containing the graph is shown in the attachment
Answer:
20% of the class earned a D
Step-by-step Explanation:
Step 1: Determine the total number of students represented on the graph:
9 students => D
5 students => C
14 students => B
17 students => A
Total number of students = 45
Step 2: Express each category of students who scored a particular grade as a fraction and as percentage.
9 students => D => => as percentage, we have
5 students => C => => as percentage, we have
14 students => B => => as percentage, we have
17 students => A => => as percentage, we have
Step 3: Check each statement to see if they are true or not based on the calculations above.
Statement 1: "⅕ of the students earned a C."
This is NOT TRUE From our calculation, ⅑ of the students earned a C.
Statement 2: "3% more students earned an A than a B." This is also NOT TRUE.
37.8% earned A, while 31.1% earned a B. Thus, about 6.7% more students earned an A than a B.
Statement 3: "20% of the class earned a D". This is TRUE.
Check calculation in step 2.
Statement 4: "¼ of the class earned a B". This is NOT TRUE.
¼ is 25% of the class. Those who earned a B account for 31.1% not 25% (¼ of the class).
The correct statement is: "20% of the class earned a D"
Answers
25+40 = 65
Answer: 65
The error made is that the random simulation is perfectly going to match up with the theoretical values. It never works out this way. Though as the number of trials increases, it should get closer and closer.