MATHEMATICS HIGH SCHOOL

What are the coefficients in the polynomial 5x^2 + 2x - 4?A: 5, 2
B: -5, -2
C: 5, 2, -4
D: 5, -2, -4

Answers

Answer 1

Answer:

The solution is, A) 5, 2 are the coefficients in the polynomial 5x^2 + 2x - 4.

What are Polynomials?

Polynomials are sums of k-xⁿ terms, where k can be any number and n can be any positive integer.

here, we have,

given that,

the polynomial is : 5x^2 + 2x - 4

now, we have to find the coefficients in the polynomial 5x^2 + 2x - 4

we know that,

a coefficient is a multiplicative factor in some term of a polynomial, a series, or an expression; it is usually a number, but may be any expression. When the coefficients are themselves variables, they may also be called parameters.

and. we have,

a variable is a symbol that represents a mathematical object. A variable may represent a number, a vector, a matrix, a function, the argument of a function, a set, or an element of a set.

so, we get,

a coefficient is the number in front of the variable,

here, 5, 2 are the coefficients.

and the variable is x.

Hence, The solution is, A) 5, 2 are the coefficients in the polynomial 5x^2 + 2x - 4.

Know more about Polynomials here:

brainly.com/question/2833285

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Answer 2

Answer: A) 5, 2
Because a coefficient is the number in front of the variable, and the variable is x.

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Solve the equation for y (Y-3)^2=4y-12

Answers

If you would like to solve the equation for y, you can do this using the following steps:

(y - 3)^2 = 4y - 12
y^2 - 6y + 9 - 4y + 12 = 0
y^2 - 10y + 21 = 0
(y - 7) * (y - 3) = 0
1. y = 7
2. y = 3

The correct result would be y = 7 or y = 3.

What is the lowest common denominator of 20 and 24

Answers

the lowest common denomenator is the smallest common factor of them so
20=1 times 2 times 2 times 5
24=1 times 2 times 2 times 2 times 3
the lowest common denomenator is 1

I think the question should have been. what is the greatest common factor (4) or what is the smallest common multiple (120)

How do you find rhe slope of (12,-18) and (-15,-18)

Answers

slope of 2 points is
if you has the points
(x1,y1) and (x2,y2)

slope=(y2-y1)/(x2-x1)

we are given
(12,-18)
(-15,-18)

we can either take shortcut and recocnize that -18-(-18)=0 so that make the slope 0

or we can continue
(-18-(-18))/(-15-12)=0/-27=0

slope=0

you do Y2-Y1/ X2-X1, so -18--18(change sighn so it would be -18+18) which equals 0, then -15-12= -27, 0/-27= 0 so the slope would be 0

Mike is pouring a two foot cement sidewalk around the perimeter of his swimming pool. His swimming pool measures 6 feet by 14 feet. If he plans for the sidewalk to be 9 inches deep, what volume of cement is needed for the sidewalk?

Answers

9 inches * 1 foot / 12 inches
= 3/4 feet deep

Area of the sidewalk:
= the sides of the pool * the width of the sidewalk + the corners of the sidewalk (width * width)
= 2 sides * 6 (feet / side) * 2 feet + 2 sides * 14 (feet / side) * 2 feet + 4 corners * (2 feet * 2 feet / corner)
= 12 feet * 2 feet + 28 feet * 2 feet + 4 * 2 feet * 2 feet
= 24 feet^2 + 56 feet^2 + 16 feet^2
= 96 feet^2

Volume:
= 96 feet^2 * 3/4 feet
= (96 * 3 / 4) feet^3
= (19 * 3) feet^3
= 57 feet^3

Answer:

the correct answer is B) 72^ft 3

Find the product of (x − 3)2.
x2 + 6x + 9
x2 − 9
x2 − 6x + 9
x2 + 9

Answers

(x-3)² ⇒ (x-3)(x-3)

(x-3)(x-3) = x(x-3) -3(x-3) ⇒ x² - 3x - 3x + 9 ⇒ x² - 6x + 9

The 3rd option is the correct answer. x² - 6x + 9

Answer:

$\large\boxed{x^2-6x+9}$

Step-by-step explanation:

$(x-3)^2\n\n\bold{METHOD\ 1}\n\n(x-3)^2=(x-3)(x-3)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\n\n=(x)(x)+(x)(-3)+(-3)(x)+(-3)(-3)\n\n=x^2-3x-3x+9\qquad\text{combine like terms}\n\n=x^2-6x+9\n\n\bold{METHOD\ 2}\n\n(x-3)^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\n\n=x^2-2(x)(3)+3^2\n\n=x^2-6x+9$