Answer:
Real number
Step-by-step explanation:
Those are the Real numbers.
Real numbers (R) are the conjoint of Rational Numbers (Q) - those than can be written as a fraction, e.g., 4/3, 80/456, etc. - and Irrational Numbers (I) - those that CAN'T be represented by a fraction, e.g., pi number.
So R = Q ∪ I
The dimensions that give the maximum area is 5 cm by 5 cm.
Given:
The perimeter of this rectangle is 20 cm, and formula for perimeter is
P= 2(W+L)
P = 20 cm = 2W + 2L.
Then W + L = 10 cm,
or W = (10 cm) - L.
The area of the rectangle is A = L·W, and is to be maximized.
On substituting the values, we get A = L[ (10 cm) - L ], or A = 10L - L²
Note that this is the equation of a parabola that opens down. With coefficients a = -1, b = 10 and C = 0, we find that the x-coordinate of the vertex (which is the x-coordinate of the maximum as well) is
x = -b / (2a). Subbing 10 for b and -1 for a, we get:
x = -[10] / [2·(-1)] = 10/2, or 5.
This tells us that one dimension of the rectangle is 5 cm.
Since P = 20 cm = 2L + 2W, and if we let L = 5 cm, we get:
20 cm = 2(5 cm) + 2W, or
10 cm = W + 5 cm, or W = 5 cm.
Therefore, choosing L = 5 cm and W = 5 cm results in a square, which in turn leads to the rectangle having the maximum possible area.
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Answer:
5 cm by 5 cm
Step-by-step explanation:
The perimeter of this rectangle is 20 cm, and the relevant formula is
P = 20 cm = 2W + 2L. Then W + L = 10 cm, or W = (10 cm) - L.
The area of the rectangle is A = L·W, and is to be maximized. Subbing (10 cm) - L for W, we get A = L[ (10 cm) - L ], or A = 10L - L²
Note that this is the equation of a parabola that opens down. With coefficients a = -1, b = 10 and C = 0, we find that the x-coordinate of the vertex (which is the x-coordinate of the maximum as well) is
x = -b / (2a). Subbing 10 for b and -1 for a, we get:
x = -[10] / [2·(-1)] = 10/2, or 5.
This tells us that one dimension of the rectangle is 5 cm.
Since P = 20 cm = 2L + 2W, and if we let L = 5 cm, we get:
20 cm = 2(5 cm) + 2W, or
10 cm = W + 5 cm, or W = 5 cm.
Thus, choosing L = 5 cm and W = 5 cm results in a square, which in turn leads to the rectangle having the maximum possible area.
.15x=12
x= 12/.15
x= 80
15% of 80 equals 12
I hope that's help !
To find the number of rows of trees in the parcel, we set up the equation (Number of rows) * (3x - 2) = 24x - 16. By solving this equation for the number of rows, we find that it equals (24x - 16) / (3x - 2).
The question is about determining the number of rows in a rectangular parcel of land with trees. It is given that each row has 3x-2 trees and the total is 24x-16 trees. We can set an equation based on this information: (Number of rows) x (Number of trees in each row) = Total number of trees. This gives us the following equation: (Number of rows) * (3x - 2) = 24x - 16. Solving for the number of rows, we divide each side of the equation by 3x - 2. Hence, the number of rows equals (24x - 16) / (3x - 2).
#SPJ12
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Explanation:
Use the remote interior angle theorem. This says a pair of interior angles always add to the measure of the exterior angle that is not adjacent to any of the interior angles, so basically what your diagram is showing.
(interior angle C) + (interior angle D) = exterior angle
(46) + (-1+8x) = 18x+5
8x+45 = 18x+5
8x-18x = 5-45
-10x = -40
x = -40/(-10)
x = 4