The weights of four packets of sugar are shown below:Packet A: 4.35 pounds
Packet B: 4.42 pounds
Packet C: 4.48 pounds
Packet D: 4.39 pounds


Sandy has a scale that measures to the nearest tenth of a pound. If Sandy weighs each packet on her scale, the heaviest reading will be _____ pounds.

Answers

Answer 1
Answer: 4.35=4.4
4.42=4.4
4.48=4.5
4.39=4.4

Highest will be 4.5 pounds.
Answer 2
Answer:

Answer:

packet C : 4.50 pounds

Step-by-step explanation:


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Which events are mutually exclusive?Jon eats 2 apples; Jon eats 4 apples.

Jon eats 4 apples; Jon eats 1 apple.

Jon eats more than 1 apple; Jon eats 3 apples.

Jon eats 2 apples; Jon eats more than 2 apples.

Answers

the last one is I think

15. Angle AOD has what measurement according to the protractor?

Answers

Answer:

90 degrees

Step-by-step explanation:

We can see in the attachment that AOD extends from 0 degrees to 90 degrees, creating a 90 degree or right angle.

Hope this helps! :)

Help, ! I’m so lost at this point.

Answers

Remember PEMDAS

Parentheses

Exponents

Multiply/Divide

Add/Subtract

in that order

If z = -7, what is the value of (-8z) - z?

Answers

Answer:

63

Step-by-step explanation:

you will plug in -7 for both z's

(-8(-7) - (-7)

following PEMDAS you will do multiplication first

(-8(-7) = 56

now we have 56 - (-7)

since - and - make a positive it will be

56 + 7 = 63

Answer question in the picture for brainliest and 10 points.

Answers

Answer:

D

Step-by-step explanation:

I know because I am smart. Trust me, it is D.

Its D

Step-by-step explanation:

pwease ik

a rectangular field with a area of 8000m2 is enclosed by 400m of fencing. determine dimensions to nearest tenth of a metre

Answers

field:x\ *\ y\n\n \left\{\begin{array}{ccc}x\cdot y=8000\n2x+2y=400&/:2\end{array}\right\n\left\{\begin{array}{ccc}x\cdot y=8000\nx+y=200&\to x=200-y\end{array}\right\n\nsubstitute\ to\ x\cdot y=8000\n\n(200-y)\cdot y=8000\n\n-y^2+200y-8000=0\n\n\Delta=b^2-4ac;\ \Delta=200^2-4\cdot(-1)\cdot(-8000)=40000-32000=8000\n\ny_1=(-b-\sqrt\Delta)/(2a);\ y_2=(-b+\sqrt\Delta)/(2a)

\sqrt\Delta=√(8000)=√(1600\cdot5)=40\sqrt5\n\ny_1=(-200-40\sqrt5)/(2\cdot(-1))=(-200-40\sqrt5)/(-2)=100+20\sqrt5\approx144.7\ (m)\n\ny_2=(-200+40\sqrt5)/(2\cdot(-1))=(-200+40\sqrt5)/(-2)=100-20\sqrt5\approx55.3\ (m)\n\nx_1\approx200-144.7=55.3\ (m)\n\nx_2\approx200-55.3=144.7\ (m)\n\nAnswer:Dimension of the field is:55.3m\ *\ 144.7m