Any two triangles can be joined to make a rhombus? correct or incorrect. if is incorrect explain.
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Incorrect; Only two isosceles triangles can form a rhombus.
Incorrect. It will only work with two isosceles triangles because of the lengths of the sides.
Twitter allows companies to reach consumers with
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Answer:
Short personal messages
Step-by-step explanation:
Solve the equation 4 1/5+b= 9 3/5 b=---
and if you could work it out and show me that would help a lot.
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4 1/5 + b = 9 3/5
4 1/5 - 4 1/5 + b = 9 3/5 - 4 1/5 (taking the same amount from each side to keep it balanced)
0 + b = 5 2/5 (subtracting 4 1/5 from each side)
b = 5 2/5
4 1/5+b=9 3/5 convert to improper fraction 21/5+b=48/5 since they both have the same denominators,you can subtract the numerators b= 48/5-21/5 b=27/5= 5 2/5
hope this helps
HELP ME FAST BECAUSE I AM TIMEDIf NTM is congruent to OUM, SP is congruent to SQ, S is the center of the circle, and OM = 18, find NT. Round the answer to the hundredths place.
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we know that , in a circle radius perpendicular to chord will bisect the chord. OM=18, so OQ=QM=18/2=9. Given QU=8 from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2 OU^2 = 9*9 + 8*8 = 81+72=153; OU=sqrt(153) = 12.37 =13(approx); From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
A rectangular garden is 8 feet long and 4 feet wide. A second rectangular garden has dimensions that are 54 the dimensions of the first garden. What is the percent of change in perimeter from the first garden to the second garden?ftyrt
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We have the perimeter of first dimension 2(8 + 4) = 24; The perimeter of the second dimension is 2( 8 + 54 + 4 + 54 ) = 240 We calculate p/100 = 24/240; Then p/100 = 1/10; p = 100/10; p = 10; Finally, 10% is the answer.
Use Order of Operations to simplify. 42 – (28 ÷ 7) + 111
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do parentheses first which gives you 42-4+111 then aubtract to get 38+111 which equals 149