Simplify the expression. 12^–3 • 12^10 • 12^0A. 1

B. 1728^7

C. 12^7

D. 36^7

Answers

Answer 1

Answer: since they have the same base we can just add all the exponents

-3+ 10= 7

keep the base so the answer is
12^7

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Given quadrilateral ABCD ~ quadrilateral JKLM and AD = 14, JM = 6, and KL = 9, what is BC?----------------------

Answers

BC= 26
detailed solution is attached

Find the area of the shaded sector (It is 45 degrees with a radius of 7) Help!!!

Answers

Answer:

Step-by-step explanation:

The formula for the area of a sector is

$A_(s) =(\theta )/(360)*\pi r^2$

where theta is the angle given as 45 and r is the radius (7). Plugging in we get

$A_(s)=(45)/(360)*\pi (7)^2$

Simplify a bit to get

$A_(s)=(1)/(8)*49\pi$

which gives you, in terms of pi:

$A_(s)=(49\pi )/(8)$

or if you need to use the decimal form, rounded to the hundredths position:

A = 19.24

E 125° G F mZGFH = [?]° H

Answers

Answer:

∠ GFH = 55°

Step-by-step explanation:

∠ GFH and ∠ GFE are a linear pair and sum to 180° , that is

∠ GFH + ∠ GFE = 180°

∠ GFH + 125° = 180° ( subtract 125° from both sides )

∠ GFH = 55°

How to find simplify the ratio 25:35

Answers

5:7

Step-by-step explanation:

To simplify the ratio 25:35, you can divide both numbers by their greatest common divisor (GCD). In this case, the GCD of 25 and 35 is 5. So, dividing both numbers by 5 gives us the simplified ratio: 5:7.

Answer:

25:35 or 25/35 = 5/7 or 5:7

Step-by-step explanation:

1. Start with the ratio 25:35.

2. Find the HCF of 25 and 35. The HCFof 25 and 35 is 5.

3. Divide both numbers in the ratio by the HCF.

25 ÷ 5 = 5

35 ÷ 5 = 7

4. The simplified ratio is 5:7.

Therefore, the simplified form of the ratio 25:35 is 5:7.

What percent of 32.2 is 24.15

Answers

100%/x%=32.2/24.15
(100/x)*x=(32.2/24.15)*x - we multiply both sides of the equation by x
100=1.33333333333*x - we divide both sides of the equation by (1.33333333333) to get x
100/1.33333333333=x
75=x
x=75

now we have:
24.15 is 75% of 32.2

Solve the system of inequalities by graphing.
y<-4X – 1
y > 6x+7