Barry wants to make a drawing that is the size of the original. If a tree in the original drawing is 14 inches tall and 5 inches wide, what will be the length and width of the tree in Barry's drawing?

Answers

Answer 1

Answer: 14/4 = 7/2
5/4 cannot be simplified.
The tree's parameters will be 3 1/2 inches tall and 5/4 inches wide.

Related Questions

Find an equation of a line that pass through (4,3) and parallel to y=-4x+1
Answer the question.
coach currans team has won 5 times and lost 2 times.He hopes that his team can keep this same ratio of wins to losses.If the team has 10 losses,how many wins would they need to keep the record
If the rate of change is the same on the entire graph we say it has a ____ rate of change.
Compare 3.21 and 0.2

Which pair of ratios is proportional? A. 5/7 and 25/35 B. 6/9 and 18/26 C. 9/18 and 16/36 D. 35/120 and 75/240

Answers

The answer is A bcause 5×5/7×5=25/35.

Its A: $(5)/(7)$ = $(25)/(35)$
because $(5*5)/(7*5)$ = $(25)/(35)$
the others do not have a common number multiplied in the numerator and denominator.
Note: If the numerator and Denominator are multiplied by the same number, it is proportional.
In this example, it was multiplied by 5

a park has the shape of a trapezoid. two of the sides are 25 meters long. the other two sides are 40 meters and 20 meters long. what is the perimeter of the park?

Answers

Perimeter is just the distance around. You add the side lengths which are all given. The sum is 110.

Polygon ABCDEF is a regular hexagon. Find the perimeter of the polygon. Round to the nearest hundredth. Round to give final answer only.

Answers

Answer:

12√2 ≈ 16.97

Step-by-step explanation:

Points A and B are on grid lines. The difference B-A is (2, 2), so the distance formula will tell you the length of that segment is ...

√(2²+2²) = 2√2

The regular hexagon has 6 sides all the same length. The perimeter is the sum of those lengths, so is ...

6 × 2√2 = 12√2 ≈ 16.97 . . . . units

Consider the following relation: {(1,12), (3,8), (3, 11), (6,9), (7,11)). Which orderedpair could be removed so that the relation is a function?

Answers

Answer:

(3,11) or (7,11)

Step-by-step explanation:

A function cannot have the same second number repeated ( forgot the term for the second number) so removing either (3,11) or (7,11) would leave it being a function

Can I please get some help with problems (b) and (c)? I'm not sure how to figure it out. Diagram listed below.