Please answer ASAP! An explanation is a MUST REQUIREMENT in order to receive points and the Brainliest answer. Thank you.
Please answer ASAP! An explanation is a MUST REQUIREMENT in - 1

Answers

Answer 1
Answer: it would be the second one because it have a bigger value

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What decimal is equal to six tenths

Answers

6 tenths
it is 6/10 as a fraction which is equal to 0.6 as a decimal

The weight of an object on the moon is 1/6 it's weight on Earth. Write 1/6 as a decimal.

Answers

to write 1/6 as a decimal ,you divide 1/6....so u get ..0.1666666..... It goes on so we can take its rounded value..i.e,0.1666667..Hope i am right!!!!

Find each quotient
-7/12 divided by 1/7

Answers

Answer:

-4  1/12

i just put it in a calculator

How many roots do the following equations have? -12x^2 - 25x+5 +x^3=0

Answers

Answer:

There are 3 roots of the given equation.

Step-by-step explanation:

Given the equation      

-12x^2-25x+5+x^3=0

we have to tell the number of roots of the given equation.

As the number of roots for an equation is equal to degree.

The degree of a polynomial is the highest power of its monomials  with non-zero coefficients.

Hence, number of roots is the highest power in the equation.

Now, the equation is -12x^2-25x+5+x^3=0

The highest power i.e degree of equation is 3.

hence, there are 3 roots of the given equation.

-12x^2 - 25x + 5 + x^(3) = 0
x^(3) - 12x^(2) - 25x + 5 = 0
x = \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) + \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} + \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) - \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} - (b)/(3a)
x = \sqrt[3]{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) + \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3)}} + \sqrt[3]{((-(-12)^(3))/(27(1)^(3))}} + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) - \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3) - (-12)/(3(1))}}
x = \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) + \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} + \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) - \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} - (-12)/(3)
x = \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) + \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} + \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) - \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} - 4
x = \sqrt[3]{(64 + 50 - 2(1)/(2)) + \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} + sqrt[3]{(64 + 50 - 2(1)/(2)) - \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} - 4
x = \sqrt[3]{(114 - 2(1)/(2)) + \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} + \sqrt[3]{(114 - 2(1)/(2)) - \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} - 4
x = \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - 4
x = \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} + \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} - 4
x = \sqrt[3]{112(1)/(2) + √(-1751.787)} + \sqrt[3]{112(1)/(2) - √(-1751.787)} - 4
x = \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i} - 4
x = -4 + \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i}

The population of Germany is about how many times the population of Martinique?Explain your reasoning.Germany: 8.27*10^7
Martinique: 4.05*10^5

Answers

We have to take the population of Germany divided by the population of Martinique:
(8.27*10^7)/ (4.05*10^5)= 204.198.

Conclusion: The population of Germany is about 204 times as large as the population of Martinique.

Hope this helps~

If c=12 find a right triangle 90 degrees 45 degrees 45 degrees

Answers

If is a triangle 90°, 45°, 45° then the sides are in ratio 1 : 1 : √2.

If c = 12 is a hypotenuse, therefore we have the equation:

a\sqrt2=12\ \ \ \ |\cdot\sqrt2\n\n2a=12\sqrt2\ \ \ \ |:2\n\n\boxed{a=6\sqrt2}

If c = 12 is a leg, therefore we have:

\boxed{a=12\sqrt2}