(x-2)*(x+2)
Distribute
(x)(x)+(x)(2)+(-2)(x)+(-2)(2)
x²+2x-2x-4
= x²-4
I hope that's help;0
The total value of the 12 bills is $115.
How many $5 bills and how many $10 bills does he have?
A: 6x^2 - 9x
B: -7x - 8x
C: -7x^2 + 8x
D: 7x + 8x
2. 3k^3(-2k^2 - 4k + 7)
A: -6k^3 - k + 10k
B: -6k^4 - 12k^3 + 21k^2
C: k^4 - k^3 + 10k2
D: 6k^4 - 12k^3 + 10k^2
3. (2k + 1) (k - 4)
A: 2k^2 - 7k + 4
B: 2k^2 - 3k + 4
C: 2k^2 + 9k + 4
D: 2k^2 - 7k - 4
4. (-2y + 5) (y + 3)
A: -2y^2 + 8y + 15
B: -2y^2 - y + 15
C: 2y^2 + 8y + 8
D: 2y^2 - y + 8
3.1 x 10^8 3.1 x 10^7 3.1 x 10^–8 31 x 10^7 5. What is the solution to (4 x 10^3) x (6 x 10^6), written in scientific notation?
24 x 10^9 2.4 x 10^9 24 x 10^18 2.4 x 10^10 8 What is 0.00000512 in scientific notation? 5.12 x 106 512 x 105 5.12 x 10–6 512 x 10–5 9 What is thirty-one over five written as a decimal? 1.6 6.1 6.2 6.5 My answers are: 1. 17/25 2. 1/8 4. 3.1 x 10^8 5. 2.4 x 10^9 8. 5.12 x 10^6 9. 6.1
Answer:
Let's solve the problem step-by-step:
We are given that the sum of three numbers is 2100. Let's call the first number x and the other two numbers y and z.
From the information given, we know that x = y + z, and y = z (the other two numbers are equal to each other).
Substituting y = z into x = y + z, we have x = 2z.
We are also given that the sum of the three numbers is 2100. So, we can write the equation x + y + z = 2100.
Substituting x = 2z and y = z, we have 2z + z + z = 2100.
Simplifying the equation, we have 4z = 2100.
Dividing both sides of the equation by 4, we find z = 525.
Substituting z = 525 back into y = z, we find y = 525.
Finally, substituting z = 525 and y = 525 back into x = 2z, we find x = 1050.
Therefore, the three numbers are x = 1050, y = 525, and z = 525.
Among the options provided, the correct answer is A) (1050, 525, 525).