b) The dilution equation works because the molarity remains the same.
c) The dilution equation works because the volume remains the same.
d) The dilution equation works because the number of moles remains the same.
Answer:
d) The dilution equation works because the number of moles remains the same.
Explanation:
Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and M₁V₁ = 1 mol.
Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.
The volume has doubled, but the volume has halved, and M₂V₂ = 1 mol.
b) Wrong. The molar concentration changes on dilution.
c) Wrong. The volume changes on dilution.
a) Wrong, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula M₁V₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.
The dilution equation work M1V1 =M2V2 work because the number of moles of solute remains the same.
Dilution refers to the addition of solvent such as water to a solution. When dilution is done the amount of solute is not affected but the amount of solvent increases while the concentration decreases.
It is the opposite of dilution where by a solvent is removed from a solution thereby increasing the concentration of the solute.
The dilution equation is given by;
M1V1=M2V2
Where M1 is the initial concentration of the solution
V1 is the initial volume of the solution
M1 is the concentration of the new solution
V1 is the volume of the new volume
Initial solution
The initial solution before dilution is called the stock solution. It is the solution before dilution process is done.
Final solution is called the diluted solution. It is the solution obtained after the process of dilution.
Since dilution involves addition of solvent, then the amount of solvent in this case water increases , the amount of solute remains constant while the concentration of solute decreases.
Keywords: Dilution, dilution equation, stock solution, diluted solution.
Dilution: brainly.com/question/3203632
Dilution equation: brainly.com/question/7208939
Application of dilution equation; brainly.com/question/7208939
Level: High school
Subject: Chemistry
Topic: Mole
Sub-topic: Dilution
Show what the following molar ratios should be.
a. C4H10 / O2 2:13 (example) b. O2 / CO2
c. O2 / H2O
d. C4H10 / CO2
e. C4H10 / H2O
also give an explanation
Answer:
a. C₄H₁₀/O₂ = 2:13 (example)
b. O₂/CO₂ = 13:8
c. O₂/H₂O = 13:10
d. C₄H₁₀/CO₂ = 2:8
e. C₄H₁₀/H₂O = 2:10
Explanation:
2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O
The molar ratios are the same as the coefficients in front of the formulas.
Liver cells, which require a high amount of energy, contain large numbers of mitochondria, the organelles responsible for energy production in the form of ATP.
The cell organelles that you would expect to appear in large numbers in liver cells, which require a great deal of energy, are mitochondria. Mitochondria, often referred to as the 'powerhouses of the cell, are responsible for producing a molecule called adenosine triphosphate (ATP), which is the main source of cellular energy. Therefore, cells that require a lot of energy, like liver cells, tend to have many mitochondria in order to meet their energy demands.
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