The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:~ y = (1/20)x²
~ y = -(1/20)x²
~ x = (1/20)y²

Answers

Answer 1
Answer:

The equation of parabola will be y=(1/20)x² .

Given,

Focus : (0, 5)

Directrix : y = -5

Now,

The standard equation of parabola is : x² = 4ay or y² = 4ax .

Focus is above directrix, it opens up

x²=4ay

a is distance from directrix to vertex

Since it opens up, a is positive

from -5 to 0 is 5 units

x²=4(5)y

x²=20y

solve for y

divide both sides by 20

y=(1/20)x²

Know more about parabola,

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Answer 2
Answer: for a parabola at vertex (0,0)
we see that we have to go up and down
therfor it opens up or down

since focus is above directix, it opens up
x^2=4Py
p is distance from directix to vertex
since it opens up, P is positive
from -5 to 0 is 5 units
x^2=4(5)y
x^2=20y
solve for y
divide both sides by 20
y=(1/20)x^2

first one

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Answers

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Answers

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Answer:

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Answers

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Answers

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Answers

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Answers

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