(2x^2 -x+5)v+ (3x^2 -3x -2)

Answers

Answer 1

Answer: 5x^2 - 4x +3
explanation is attached
Enjoy !

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Complete the square x^2+x+8x

Can someone explain to me how to do this? :

8^2y+4 = 16^y+1

Answers

Answer:

y = -4

Step-by-step explanation:

Assuming the problem is $8^(2y+4)=16^(y+1)$ , it would be nice if we could convert both sides of this equation to the same base; that way, we could compare the exponents directly in an equation of their own. Fortunately, 8 and 16 are both powers of 2 -- $2^3$ and $2^4$ , we can rewrite the original equation by substituting those in:

$(2^3)^(2y+4)=(2^4)^(y+1)$

When you have an exponent raised to another exponent, you multiply those exponents together, so we can simplify our equation by distributing a 3 in the left exponent and a 4 in the right:

$2^(3\cdot(2y+4))=2^(4\cdot(y+1))\n2^(3\cdot2y+3\cdot4)=2^(4\cdot y+4\cdot1)\n2^(6y+12)=2^(4y+4)$

With both of our bases the same, we can now simply compare their exponents directly to solve for y:

$6y+12=4y+4\n2y=-8\ny=-4$

Which of the following is true of the data set represented by the box plot?A.the greatest value in the set is 79
B. The data is evenly distributed throughout the middle half
C. The data has an IQR of 45
D. Removing the outliers would not affect the median

Answers

It would be D, using process of elimination ;))

Answer: D.

Step-by-step explanation: The rest are wrong

During a race, a sprinter increases her speed from 5.5 n/s over a period of 1.5 seconds. What is the sprinter's average acceleration? Show all your work and include units Vf = 7.5 m/s , Vi = 5.5 m/s , t = 1.5s Acceleration vs-vi/time

Answers

Answer:vf

Step-by-step explanation:

Using line plot write a number sentence to find the range of the data

Answers

To find the range of data you would have to subtract the smallest number from the largest number in the set. to do this on a number line you would have to find two points on a number line and subtract those two numbers

How do you find the iqr

Answers

The interquartile range (IQR) is the difference between the third and first quartiles $Q_3-Q_1$ .

Answer:

Find the median: (the middle number in the data set).

Find both the upper and lower quartile.

The subtract the upper quartile to the lower quartile, and you get the final answer of an interquartile range.

A square has an area of 49 square feet. what is the perimeter of the square?

Answers

I hope this helps you

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