MATHEMATICS COLLEGE

4^-1+2^-3
simplify !!!

Answers

Answer 1
Answer:

Answer:

3/8 (decimal = 0.375)

Step-by-step explanation:

apply exponent rule

= 1/4 + 2^-3

= 1/4 + 1/2^3

= 1/4 + 1/8

least common deno

= 2/8 + 1/8

= 3/8

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Need someone’s help with this please!!!

Answers

i think it’s option 3, 1/3

Determine the next step for solving the quadratic equation by completing the square. 0 = –2x2 + 2x + 3

Answers

Answer:

-1/2, 1/4, 1/2 on edge
The  next step is to divide the equation by -2

-2(x^2 - x) + 3 = 0

Let f(x)=3x+5, g(x)=2^x
Find f(g(x))

Answers

Answer:

The expression will be 3(2^x) + 5

Step-by-step explanation:

In order to find the new expression, you have to let g(x) be the x :

f(x) = 3x + 5

g(x) = {2}^(x)

fg(x) = 3( {2}^(x) ) + 5

What is 421906 rounded to the nearest hundred thousand

Answers

Answer:

421906

is 421910 to the nearest hundred thousand

Thien and her friends earned $80 washing cars. Thien received $30 from this amount.What is Thien's share as a percentage of the total amount earned?

Answers

37.5%

You can just do 30/80

An experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.(a) If any particular experiental run involves the use of single temperature, pressure, and catalyst, how many experimental runs are possible?
(b) How many experimental runs are there that involve use of the lowest temperature and two lowest pressure?

Answers

Answer:

Step-by-step explanation:

Given that an experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.

a) Experimental runs possible if use of single temperature, pressure and catalyst is there = no of temperatures x no of pressures x no of catalysts

= 3*4*5 = 60

b) Here pressure and temperature have no choice as lowest is selected.

no of methods = no of catalysts x 1 x1

= 5
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