Answer:
38,640g
Explanation:
Since the density is in g/mL, we have to convert 2.000 liters to mil-liters to be able to successfully use the formula of M=V*D. Convert liters to mil-liters and you should have 2000mL in which you can plug into the equation of M= 2000mL*19.32g/mL, mL cancels, and you're left with 38,640g (here the significant figures are already in check).
The mass of liquid gold in a 2-liter soda bottle would be 38640 grams. This is calculated by multiplying the volume of the bottle (2 liters, or 2000 mL) by the density of liquid gold (19.32 g/mL).
Density characterizes how much mass is packed into a given volume. In this case, we know that the density of liquid gold is 19.32 g/mL. Since 1 Liter equals 1000 mL, Our soda bottle has a volume of 2.000 liters or 2000 mL. To determine the mass of the liquid gold in this volume, we perform a simple multiplication: density * volume = 19.32 g/mL * 2000 mL = 38640 grams.
So, if the 2-liter bottle is completely filled with liquid gold, the mass of the gold would be 38640 grams.
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The total number of atoms in 1.3 x 10^22 molecules of N(O)2 is 3.9 x 10^22 atoms since each molecule of N(O)2 consists of three atoms.
To answer the question of how many atoms there are in 1.3 x 10^22 molecules of N(O)2, one must be aware of the molecular composition of N(O)2. This molecule contains one nitrogen atom and two oxygen atoms, thus comprising three atoms in total. Consequently, to determine the total number of atoms, multiply the number of molecules by the number of atoms per molecule. Hence, the answer is 1.3 x 10^22 molecules * 3 atoms/molecule = 3.9 x 10^22 atoms.
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The cation is smaller.
Electronic configuration of Lithium atom is as follow,
Li = 1s², 2s¹
while, Electronic configuration of Lithium cation is as follow,
Li⁺ = 1s²
The Lithium Cation is smaller because,
i) Less Energy Levels:
As depicted in electronic configurations, the valence shell of Li atom is 2 while, that of Li cation is 1 as a result the distance of valence electrons and nucleus has decreased resulting in small size.
ii) Less Shielding Effect:
The effect in which the core electrons shield the valence electron from nucleus pull is known as shielding effect. In Li cation there are no core electrons hence, the electrons are more attracted towards proton resulting in small size.
iii) More Nuclear Charge:
In Li atom there are three protons and three electrons so, three protons attract three electrons and the game run some what balance. But, as tone electron is lost in Li Cation, the proton side gets stronger and apply more pull on electrons and made them more closer to the nucleus resulting in size decrease.
The correct statement is: The cation is smaller.
In a neutral lithium atom, there are three electrons surrounding the nucleus, distributed in different energy levels or electron shells. These electrons repel each other due to their negative charges, creating an electron-electron repulsion that tends to spread them out and increase the size of the atom.
When a lithium atom loses one electron to form a cation, it becomes positively charged. This loss of an electron reduces the electron-electron repulsion within the atom. With fewer electrons, the remaining electrons experience a stronger attraction towards the nucleus, since the positive charge of the nucleus is no longer balanced by the negative charge of the lost electron.
As a result, the remaining electrons are drawn closer to the nucleus in the lithium cation. The reduction in electron-electron repulsion and the increased attraction between the electrons and the nucleus cause the cation to have a smaller size compared to the neutral atom.
Hence, the lithium cation (Li⁺) is smaller than the lithium atom (Li)
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B. 5.74 x 10^-7 J
C. 2.07 x 10 ^15 J
D. 8.6 x 10 ^ 4 J
Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. The energy of wave is 2.08×10⁻¹⁵J.
Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave .There is a relation between energy of wave. frequency of wave
Mathematically,
E=hv
where,
E = energy of electromagnetic wave
h is planks constant having value 6.67×10⁻³⁴js
v= frequency of wave
substituting the given values
E= 6.67×10⁻³⁴js×3.12 x 10¹⁸ s⁻¹
E= 2.08×10⁻¹⁵J
Therefore the energy of wave is 2.08×10⁻¹⁵J.
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2.) Al^3+, O^2-
3.) Ca^2, ClO3-
4.) NH4+, P^3-
5.) Cu+, NO3-
Answer:
1.) NiSO₄; 2.) Al₂O₃; 3.) Ca(ClO₃)₂; 4.) (NH₄)₃P; 5.) CuNO₃
Step-by-step explanation:
We can use the criss-cross method to work out the formulas. The steps are
If we use this method, the formula for the compound formed from Na⁺, SO₃²⁻ becomes Na₂SO₃.
1.) Ni²⁺ + SO₄²⁻ ⟶ Ni₂(SO₄)₂ ⟶ NiSO₄
2.) Al³⁺ + O²⁻ ⟶ Al₂O₃
3.) Ca²⁺ + ClO₃⁻ ⟶ Ca(ClO₃)₂
4.) NH₄⁺ + P³⁻ ⟶ (NH₄)₃P
5.) Cu⁺ + NO₃⁻ ⟶ CuNO₃