The values of a, b, and c in the quadratic equation –2x^2 + 4x – 3 = 0 are: a = -2, b = 4, and c = -3.
The values of a, b, and c in the quadratic equation –2x^2 + 4x – 3 = 0 are:
a = -2
b = 4
c = -3
In a quadratic equation in the form ax^2 + bx + c = 0, the coefficients a, b, and c represent different values. In this equation, -2 is the coefficient of the x^2 term, 4 is the coefficient of the x term, and -3 is the constant term.
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Answer:
The area of the oil spill is increasing at a rate 180 π m²/s, when the radius is 30 m.
Step-by-step explanation:
Derivative Rule:
Given that
The radius of the oil spill increases at a rate 1.5 m/s.
i.e
We need to find the rate of area increase i.e .
We know,
The area of the oil spills A = ( since it spreads in circular pattern)
Differentiating with respect to t
Plug the value of
Plug r= 30 m
=180 π m²/s
The area of the oil spill is increasing at a rate 180 π m²/s, when the radius is 30 m.
4x2 + 40x + 100
4x2 + 100
4x2 − 40x + 100
Answer:
Step-by-step explanation:
Given the expression
we have to simplify the above expression.
By identity
Put a=2x and b=10
Option B is correct.