PHYSICS HIGH SCHOOL

In a game of darts, the dart thrower releases the dart directly at the center of the target (the "bull’s eye") with a speed of 13.0 m/s, and the dart strikes the wall, 0.23 m directly below the center of the target. How far from the wall, along the x-axis, was the dart released?

Answers

Answer 1

Answer:

Answer:2.81 m

Explanation:

Given

speed(u)=13 m/s

dart strikes 0.23 m below

i.e. vertical distance traveled by dart is 0.23 m

considering dart motion similar to Projectile

$h=ut+(at^2)/(2)$

$0.23=0+(9.8t^2)/(2)$

$t=0.216 s$

Horizontal distance travel by dart =u\times t

$=13* 0.216=2.81 m$

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First year profit: $1000*12 = $12,000
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:

In this exercise we have to use the knowledge of finance to calculate the profits that Korey expect to make is $15,149.72.

So organizing the information given in the statement we find that:

average $1,000 of profit
6% each year for the next 4 years

Doing these calculations we find that:

$1000*12 = $12,000\n12,000 * 1.06^1\n12,000 * 1.06^2\n12,000 * 1.06^3\n12,000 * 1.06^4 =$15,149.72$

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