MATHEMATICS HIGH SCHOOL

What is the equation of the line that passes through the points (−2, 3) and (2, 7)?x − y = −1

x − y = −2

x − y = − 5

x − y = − 6

Answers

Answer 1
Answer: Hello,

y-3=(7-3)/(2+2)(x+2)==>y-3=x+2==>x-y=-5
Answer C

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If (7, m) is on a circle with center C(−2, 2) and radius 9, what is the value of m?

Answers

First thing I did was check the distance between the point and the center of the circle on the x-axis, because that was the information already given. Turns out that 7 - (-2) = 9, and so m is equal to the y-value of the center of the circle.

m = 2

Hope that helps!

Can you please help me? It’s timed!!

Answers

Answer:

0.75 (D)

Step-by-step explanation:

tanA = (6)/(8)

tanA = 0.75
The answer is D hope this helps

How many ounces is 2.5 pounds of copper

Answers

this is equal to 40 oz

What is the equation of the axis of symmetry of the graph of y3x-6-3(x-2)2 4?

Answers

The answer is y^3-24x+42

how do you find the volume to the nearest cubic in of a cone whose radius is 12 in and hieght is 15 inches

Answers

You have to know the formula for the volume of a cone.
In high school, there's no other way.

Volume of a cone = (1 / 3) π (radius)² (height)

Volume = (1 / 3) π (12 inches)² (15 inches)

Volume = 720 π = 2,261.95 cubic inches

Rounded to the nearest cubic inch, that's 2,262 cubic inches.
V \beta = (1)/(3) \pi r^(2)h \n V \beta = (1)/(3) \pi 12^(2) * 15 \n V \beta = 2160 * (1)/(3) \pi \n V \beta = 720 \pi

For the function below, state the x-coordinate of the x-intercept that is located to the fight of the origin.f(x)=x^3-9x

Answers

Answer:

x = 3

Step-by-step explanation:

It should NOT be "fight of the origin", rather "right of the origin".

Now let's move on to solve the question...

The x-intercept is found by setting the function equal to 0. Thus:

0 = x^3 - 9x

Let's solve this using algebra:

0=x^3-9x\n0=x(x^2-9)\n0=x(x-3)(x+3)

Hence, x = -3 and x = 3

The coordinate that is to the right of the origin is the positive one, so x = 3 is the x-intercept we are looking for.
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