Find the mean of this set of numbers.9, –6, –8, 11, –4, 10

A.
48

B.
2

C.
12

D.
8

Answers

Answer 1

Answer: b. 2

The mean is 12 divided by 6, or 2.

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Answers

Answer:

try 137

Step-by-step explanation:

it may be congruent since they're parallel

Compare the numbers √11 and 3.7. Use the symbols <,>,or=.

Answers

Answer: Hi! here we want to compare the numbers $√(11)$ and $3.7$

and we need to use <,> or =

So the first thing i would look is the square root.

we know that $3^(2) = 9, 4^(2) = 16$

so 3< $√(11)$ <4

now we can see $3.7^(2) = (3 + 0.7)*(3 + 0.7) = (3*3 + 2*0.7*3 + 0.7*0.7) =(9 + 6*0.7 + 0.7*0.7)$

is easy to see that $0.7*6 \geq 0.5*6=3$

then $3.7^(2) = (9 + 0.7*6 + 0.7*0.7) > (9 + 3 + 0.7*0.7) > 9 +3 = 12$

so 3.7^2 > 12, and 12>11

then: $3.7 > √(11)$

You also can use a calculator, but i think this is not the idea of the problem.

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What is 12.312 trillion in scientific notation?

Answers

The scientific notation of 12.312 trillion is $1.2312 * 10^(13)$ .

What is scientific notation?

Scientific notation is a means of representing large number numbers in standard form using power of 10.

The given number

= 12.312 trillion

There are 12 zeros in a trillion.

The scientific notation of 12.312 trillion is $12.312 * 10^(12) = 1.2312 * 10^(13)$ .

Learn more about scientific notation here: brainly.com/question/1199149

1.2312 x 10^13
A million is 10^6
A Billion is 10^9
A trillion is 10^12
12.312 trillion is 12.312 x 10^12 which is the same as 1.2312 x 10^13

Mr. Johnson has $15,000 to invest. Part of it is put in the bank at 4 percent, and part he puts in a savings and loan at 7 percent. If his yearly (simple) is $951, how much did he invest at each rate?

Answers

Answer:

$3300 at 4%

$11700 at 7%

Step-by-step explanation:

Total investment = $15000

Total simple interest on investment = $951

Investment A:

Rate = 4% =0.04

Investment B:

Rate = 7% =0.07

Simple interest (S. I) = principal * rate * time

(S. I on investment A + S. I on investment B)

Let principal amount in investment A = A

principal amount in investment B = B

(A * 0.04 * 1) + (B * 0.07 * 1) = $951

0.04A + 0.07B = $951 - - - - (1)

A + B = $15000 - - - - (2)

from (2)

A = 15000 - B

Substitute A = 15000 - B into (1)

0.04(15000 - B) + 0.07B = 951

600 - 0.04B + 0.07B = 951

600 + 0.03B = 951

0.03B = 951 - 600

0.03B = 351

B = 351 / 0.03

B = $11700

From (2)

A + B = $15000

A + $11700 = $15000

A = $(15000 - 11700)

A = $3300

The women's department of a store stocks 4 types of black socks for every 5 types of white socks. The men's department stocks 6 types of black socks for every 7 types of white socks. If each department has the same number of black socks, which department stocks more types of white socks?

Answers

Answer:

The women's department of a store stocks have more types of white socks.

Step-by-step explanation:

Given:

The women's department of a store stocks 4 types of black socks for every 5 types of white socks.

Ratio of black socks to white socks = 4 : 5

The men's department stocks 6 types of black socks for every 7 types of white socks.

Ratio of black socks to white socks = 6 : 7

Each department has the same number of black socks.

Question asked:

Which department stocks more types of white socks?

Solution:

Let each department has 100 black socks.

For women's department

4 : 5 : : 100 : white socks

$(4)/(5) =(100)/(White\ socks) \n\n By \ cross \ multiplication\n \n 4* White\ socks=100*5\n 4White\ socks=500\nBy\ \ dividing\ both \ sides\ by\ 4\nWhite\ socks=125$

For men's department

6 : 7 : : 100 : white socks

$(6)/(7) =(100)/(White\ socks) \n\n By \ cross\ multiplication\n \n 6White\ socks=100*7\n6White\ socks=700\nWhite\ socks=About\ 117$

We found that out of 100 black socks the women's department of a store stocks have 125 white socks while the men's department stocks have about 117 white socks then by default understood that the women's department of a store stocks have more types of white socks.

Answer:

The women have more

Step-by-step explanation:

Simplify (3x + 5) + (2x - 9) - (4x + 3).