Show your work !

Thanks
garydesir1 avatar

Answers

Answer 1
Answer: For 1st. 
you can solve it by general law or , 
since the coefficient of r^2 = 1 
so u should think of 2 number which if u multiple them gives you 27 and sum of them is 12 and those numbers are 9 , 3 
so the answer (x+9)*(x+3) 
2nd problem :
g^2 - 9 = (g-3)*(g+3) 
3rd problem:
2p^3 + 6p^2 + 3p +9 
1st divide it into two parts 
(2p^3 +6p^2)+    (3p+9)
from the 1st part 
take 2p^2 as a common factor and from part 2 take 3 as a common factor and the equation be like 
2p^2(p+3)  + 3(p+3)
then take (p+3) as a common factor
so (p+3)* ( 2p^2 +3 )                                                         
Answer 2
Answer: 1: (r+3)(r+9). 2: (g+3)(g-2). 3: (2p^2+3)(p+3). FOIL multiply the first, inside, outside, and last terms. add the inside and outside terms together. :)

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Someone help ASAP !!! (10 points)

What is 1/4 of 10 explain

Answers

Too many points for such a simple explanation :)) Whatever:
To get 1/4 of a number you multiply the number by 1/4. Same for any non-percent number. If the number is a percent, say, 23,5%, you first divide it by 100 to get a non-percent, then do the same, that is, multiply it by the number.
Our result is \frac{1}4*10=\frac{10}4=\frac{5}2=2\frac{1}2=2.5

On a map, two towns P and Q are 15.5 cm apart. The scale of the map is 1 cm: 4 km. Calculate the actual distance between P and Q.​

Answers

multiply 15.5 by 4

62 is the answer

Ushma and her friends went to a movie that started at 7:35 p.m. The movie ended at 9:20 p.m. Ushma got home 50 minutes after the movie ended. What time did Ushma get home? Explain how you found your answer?

Answers

10:10 P.M. Surely just 50 minutes after the movie finished at 9:20 p.m

A 1500 kg hippo is completely submerged, standing on the bottom of a lake. What is the approximate value of the upward normal force on the hippo?

Answers

Answer:

About 428 N

Step-by-step explanation:

Weight = 1,500 * 9.8 = 14,700 N

Density = Mass ÷ Volume

1,030 = 1,500 ÷ V

V = 1,500 ÷ 1,030  = 1.46 m^3.

Buoyant force = Density * g * V  

Buoyant force = 1,000 * 9.8 * (1,500 ÷ 1,030)

Buoyant force = 9,800 * (1,500 ÷ 1,030)  = 14,272 N.

Net force = 14,700 – [(9,800 * (1,500 ÷ 1,030)]

Final answer:

The upward normal force on a 1500 kg submerged hippo is approximately equal to its weight, calculated as its mass times the acceleration due to gravity (1500 kg × 9.81 m/s²), resulting in a force of 14715 N.

Explanation:

The question is asking about the upward normal force on a submerged hippo in a lake. To find this force, we must understand that the upward normal force that the ground (or in this case, the lake bed) exerts on the hippo is equal to the weight of the hippo, which is the product of the hippo's mass (m) and the acceleration due to gravity (g).

In equation form: Normal Force = m × g. Plugging in the values, we have a 1500 kg hippo and the acceleration due to gravity is approximately 9.81 m/s². Therefore, the upward normal force is:

Normal Force = 1500 kg × 9.81 m/s² = 14715 N.

This is the approximate value of the upward normal force exerted on the hippo standing on the bottom of the lake.

Learn more about normal force here:

brainly.com/question/18799790

#SPJ3

A circle is shown. A secant and a tangent intersect at a common point outside of the circle to form an angle that measure 51 degrees. The measure of the first arc formed is x degrees and the measure of the second arc formed is 160 degrees.What is the value of x?

x =

Answers

The value of x in the circle is 58°

Secant and tangent intersection

when a secant and a tangent meets outsides of a circle, the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs. Therefore,

51° = 1 / 2 (160 - x)

Therefore,

51 = 80 - x / 2

51 - 80 = - 1 /2 x

-29 = - 1 / 2 x

multiply both sides by -2

-29 ×  2 = - 1 / 2 x × -2

x = 58

Therefore, the value of x is 58 degrees

learn more on secant and tangent here;brainly.com/question/14697178

Answer:

58

Step-by-step explanation:

just did it on edg

Helpppppp which of the following features of the online textbook will allow you to receive extra instruction on a topic? A. Companion workbook
B. Visual glossary
C. Practice and problem solving workbook
D. Homework video tutors

Answers

Answer:

Option: D is correct.

( D. Homework video tutors )

Step-by-step explanation:

" Homework Video tutors:

Narrated by real school teachers, these online video tutorials provide students with homework help on key concepts of every lesson "

Hence, Homework video tutors are the online textbook which allow you to receive extra instruction on a topic.

Hence, option D is the correct answer.

i'd say D. because that's what a lot of mine have

hope this helped :D
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