The science of observing and forecasting weather conditions is called
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Answer:
Weather forecasting
Explanation:
Related Questions
Which compound has both ionic and covalent bonding?(1) CaCO3 (3) CH3OH(2) CH2Cl2 (4) C6H12O6
Repulsion is a force or interaction among the atoms in a molecule in which the atoms attract one another. a. True b. False
Write and balance the equation for the complete combustion of acetylene, C2H2. You do not need to include any phase symbols or energy changes.
1. How did Dmitri Mendeleev deal with elements that had not yet been discovered?A. He left blanks for them in his periodic table, as he predicted they would be discovered. B. He gave them names and properties and placed them in the table. C. He created them in his laboratory and placed them in the table. D. He ignored them, placing them in the table and shifting others when they were discovered. 2. Which of the following elements have properties similar to those of astatine (At)? A. F, Br, I B. Ar, S, P C. F, Ar, Ne D. Na, Mg, Al 3.What is true of the ionic size of the elements in a group as one moves from top to bottom in that group? A. Ionic size stays the same within the group. B. Ionic size does not vary in any predictable way within the group. C. Ionic size decreases from top to bottom within the group. D. Ionic size increases from top to bottom within the group.
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The pH of the resulting solution is 2.72
Data;
- volume of acid = 20mL
- density of acid = 1.05 g/ml
- mass = 1.05 * 20 = 21g
pH of a solution
The number of moles of acetic acid is
The concentration of acetic acid in 1.7L is
The equation for dissociation is
The Ka of this reaction is
The Ka of acetic acid = 1.8*10^-5
The concentration of hydrogen ion is
The pH of this solution is
The pH of the resulting solution is 2.72
Learn more on pH of a solution here;
20.0 ml of glacial acetic acid
1.70 L with water
density of the glacial acetic acid is 1.05 g/ml ; Ka = 1.8 x 10⁻⁵
1) find out how many grams of HC2H3O2 is in this glacial matter. It says here it has a density of 1.05g/mL.
So we find the grams from that => 1.05 g/mL * (20.0 mL) = 21 grams of HC2H3O2.
Convert this to moles => 21 grams (1 mol / 60 g) = 0.35 mol HC2H3O2
We then get the Ka formula from that equation so it is
Ka = [H3O+] [C2H3O2] / [HC2H3O2] (Remember H2O has an activity of 1 so we exclude it)
We know the concentration of HC2H3O2 because we have moles of HC2H3O2
Finding concentration of HC2H3O2 => 0.35 mol HC2H3O2/1.70 L = 0.20588 M - initial concentration
1.8 x 10⁻⁵ = (x) (x) / (0.20588 M - x)
1.8 X 10⁻⁵ (0.20588 M) = x²
3.70584⁻ x 10⁻⁶ = x²
x = 1.9251 x 10⁻³
pH = -log (H₃O⁺) = - log (1.9251 x 10⁻³) = -(-2.7156) = 2.7156
pH of the resulting solution is 2.7156
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Final answer:
A Brønsted-Lowry base is a species that accepts a proton (hydrogen ion) from another species. NH3, OH-, and even water itself are examples of Brønsted-Lowry bases, denoting they accept protons.
Explanation:
A Brønsted-Lowry base is a species that can accept a proton (a hydrogen ion) from another species. For instance, in a reaction between water and ammonia, NH3 is the Brønsted-Lowry base because it accepts a proton from water. This means that any species capable of accepting a proton, such as hydroxide ion (OH-), ammonia (NH3), or water itself can be considered a Brønsted-Lowry base.
For example, think about the dissociation of water:
H2O + H2O ⇌ H3O+ + OH-
In this reaction, water is acting as both a Brønsted-Lowry acid and a Brønsted-Lowry base. One water molecule donates a proton and becomes a hydroxide ion (the conjugate base), while the other accepts a proton to become hydronium (the conjugate acid).
Another example would be the ionization of ammonia in water:
NH3 + H2O ⇌ NH4+ + OH-
Here, ammonia (NH3) is the Brønsted-Lowry base as it accepts a proton from water to become ammonium (NH4+).
Learn more about Brønsted-Lowry Base here:
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Answer:
a salt
Explanation:
compounds are made of molecules but we need to mention the type of compound formed.
Answer:
A salt
Because compounds are made of molecules but we need to mention the type of compound formed.
(b). Atoms transfer electronsto form cations and anions.
(c). Ions transfer electrons to form cations and anions.
(d). Anions and cations donate electrons.
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Answer: (b). Atoms transfer electrons to form cations and anions.
Explanation:
Covalent compounds are formed by sharing of electrons takes place between non metals.Ionic compounds are formed by transfer of electrons between metals and non metals.
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Sodium atom has oxidation number of +1.
Electronic configuration of sodium:
Sodium atom will loose one electron to gain noble gas configuration and form sodium cation with +1 charge.
Chlorine atom has oxidation number of -1.
Electronic configuration of chlorine:
Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.
In sodium chloride the one electron from sodium metal gets transferred to chlorine atom and thus form an ionic bond.
Answer:
Atoms transfer electrons to form cations and anions.
Explanation:
Covalent compounds are formed by sharing of electrons takes place between non metals.Ionic compounds are formed by transfer of electrons between metals and non metals.