MATHEMATICS MIDDLE SCHOOL

a number cubes tolled 450 times. the number 3 comes up 67 times. what I's the theoretical probability of rolling a 3 ? WRITE YOUR ANSWER AS A FRACTION b. what us the experimental probability of rolling a 3 ? write your answer as a fraction

Answers

Answer 1
Answer: assuming number cube has 6 sides

probablity is (desiredoutcomes)/(total possible ouctomes)


since it is 450 times
total possible outcomes=450

experimiental probablity is the one actaully obtained by doing it
theoretical is the predicted amount

so theoretical probablity of rolling a 3 is 1 number out of 6 or 1/6 or 75 times out o 450 times

experimiental is the actaull one so67 out of 450 or 67/450

theoretical is 1/6 or 75/450
experimental is 67/450



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Answers

You will get to the store in 2 hours because 5 * 2 equals 2.


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Round each number to the nearest ten. What is the best estimate for the answer to 552.17 – 48.35 ?

Answers

So first round each number to the tens place so it would be;
550-50
And that would be 500 and so that's the best estimate. 
Hope this helps. 
520 - 50 = ?

520 - 50 = 470

500 is the best estimate

How to turn y-2x=7 into y=mx+b

Answers

Answer:

y = 2x + 7

Step-by-step explanation:

y -2x = 7

move 2x to other side by adding to both sides

y = 2x +7

Are the parentheses and brackets correct

Answers

Answer:

the range is correct

but the domain is [-3,3)
-3.3 is the doman of the graph

if (ax+2)(bx+7) = 15xsquared + cx +14 for all values of x, and a+b =8, what are the two possible values for c?

Answers

The two possible values for c are 31 and 41

Step-by-step explanation:

Given Expression:

(a x+2)(b x+7)=15 x^(2)+c x+14

a + b = 8

To expand,

Multiply a x with (b x + 7) =  a b x^(2)+7 a x

Multiply 2 with (b x + 7) = 2 b x +14

Now, combining the above, we get

         a b x^(2)+7 a x+2 b x+14=15 x^(2)+c x+14

         a b x^(2)+x(7 a+2 b)+14=a b x^(2)

When comparing both sides, we get

a b = 15, 7 a + 2 b = c

          a=(15)/(b) \text { or } b=(a)/(15)

Now, substitute above value in a + b = 8. So,

         (15)/(b)+b=8

         15+b^(2)=8 b

        b^(2)-8 b+15=0

Factorising above, we get the equation as

       b^(2)-3 b-5 b+15=0

       (b - 3) (b - 5) = 0

b = 3 and 5

If b = 3, then

       a=(15)/(b)=(15)/(3)=5

If b = 5, then

       a=(15)/(5)=3

If a = 3, b = 5

c =7 a + 2 b = 7 (3) + 2 (5) = 21 + 10 = 31

If a = 5, b = 3

c =7 (5) +2 (3) = 35 + 6 = 41

Therefore, the values of ‘c’ are 31 and 41.

4 times 1 1/5 please answer

Answers

Answer:

4 and 4/5

Step-by-step explanation:
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