The length of the shortest side of the triangle is 10cm.
It is given that congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side, the perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle.
All three corresponding sides are equal and all the three corresponding angles are equal in measure.
Let's have the variable x be the length of the shortest side.
To equate to demonstrate this problem:
Longer sides of the triangle is (1+x)
Perimeter = (x-2)*4
Therefore, the equation is 4(x-2)=(1+x)+(1+x)+x
Simplify:
4x-8=2+3x
4x=10+3x
x=10
So, the length of the shortest side of the triangle is 10cm.
Learn more about congruent triangle here:
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A:7 1/5
B:18/25
C:7/200
D:9/25
Answer:
Mason's and Eric's
Step-by-step explanation:
We are given that:
Olivia has 18 marbles ,Mason has 24 marbles,Nia has 63 marbles,and Eric has 75 marbles.
Each person packed their marbles in groups of 9.
We have to find who will have marbles left over.
Olivia has 18 marbles which can be packed as (9+9=18)
Mason has 24 marbles which can be packed as (9+9=18 and 6 will be left unpacked)
Nia has 63 marbles which can be packed as (9+9+9+9+9+9+9=63)
and Eric has 75 marbles which can be packed as (9+9+9+9+9+9+9+9=72 and 3 will be left unpacked)
Hence, Mason's and Eric's marbles are left unpacked
Answer:
40 cm²
Step-by-step explanation:
A = 2(lw + lh + wh)
= 2(4×2 + 4×2 + 2×2)
= 2(8 + 8 + 4)
= 2×20
= 40 cm²
Answer:
40cm^6
Step-by-step explanation:
surface area of this box
=2(lw+lh+wb)
=2(2×4+4×2+2×2)cm^6
=2(8+8+4)cm^6
=2×20cm^6
=40cm^6