Find the arithmetic combination of f(x) =x+2, g(x)=x-2

Answers

Answer 1

Answer:

Answer:

The arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f $*$ g)(x) = $\mathrm{x}^(2)-4$ , $\left((f)/(g)\right)(\mathrm{x})=(x+2)/(x-2)$

Solution:

Given, two functions are f(x) = x + 2 and g(x) = x – 2

We need to find the arithmetic combinations of given two functions.

Arithmetic functions of f(x) and g(x) are (f + g)(x), (f – g)(x), (f $*$ g)(x), $\left((f)/(g)\right)(\mathrm{x})$

Now, (f + g)(x) = f(x) + g(x)

= x + 2 +x – 2

= 2x

Therefore (f + g)(x) = 2x

similarly,

(f - g)(x) = f(x) - g(x)

= x + 2 –(x – 2)

= x + 2 –x + 2

= 4

Therefore (f - g)(x) = 4

similarly,

(f $*$ g)(x) = f(x) $*$ g(x)

= (x + 2) $*$ (x – 2)

= x $*$ (x – 2) + 2 $*$ (x -2)

$=x^(2)-2 x+2 x-4$

$=x^(2)-4$

Therefore (f $*$ g)(x) = $x^(2)-4$

now,

$\left((f)/(g)\right)(\mathrm{x})=(f(x))/(g(x))$

$=(x+2)/(x-2)$

$((f)/(g))(x)$ = $(x+2)/(x-2)$

Hence arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f $*$ g)(x) = $\mathrm{x}^(2)-4$ , $\left((f)/(g)\right)(\mathrm{x})=(x+2)/(x-2)$

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What is 0.15% of 43 i suck at math it will help me so much

Answers

.15% translates to
.0015, and "of" means to multiply. so .0015 multiplied with 43 is
.0645

Help please quick

Please pleas

Answers

The answer would be about 152 after you add and subtract everything.

About 152 even though its not rounded

is the area of a paperback book cover closer to 28 sqaure inches or 28 sqaure centimeters? tell how you decided

Answers

I would say 28 square inches. Imagine that we divide the number and we get 4 and seven. your average paperback book is about 4 inches wide and 7 inches tall. If we multiply it back, we get 28 square inches.
Hope it helps!
-Lacy

It would be centimeters becuase square inches is a very large area, much larger than a typical book. Therefore, the paperback book would most likely be 28 square centimeters

A square playing field has an area of 1,255 square yards. about how long is each side of the field