Answer:
There are 2 expected readings greater than 2.70 V
Solution:
As per the question:
Total no. of readings, n = 60 V
Mean of the voltage,
standard deviation,
Now, to find the no. of readings greater than 2.70 V, we find:
The probability of the readings less than 2.70 V, :
Now, from the Probability table of standard normal distribution:
Now,
Now, for the expected no. of readings greater than 2.70 V:
No. of readings expected to be greater than 2.70 V =
No. of readings expected to be greater than 2.70 V = ≈ 2
In this exercise we have to use the knowledge of force to calculate the required energies, so we have to:
a) 19094 N
b) 110.055 kPa
c) 1222 J
In the field of physics, force is a physical action that causes deformation or that changes the state of rest or movement of a given object.
a) Knowing that the force formula is defined by:
b) Knowing that the force exerted by an area is equal to the pressure in that area, we have:
c)So calculating the potential energy we have:
See more about force at brainly.com/question/26115859
Answer:
a) 19094 N
b) 110.055 kPa
c) 1222 J
Explanation:
The force on the gas is the weight plus the atmospheric pressure multiplied by the piston area
F = P + p * A
F = m * g + p * π/4 * d^2
F = 150 * 9.813 + 101570 * π/4 * 0.47^2 = 19094 N
The pressure is the force divided by the area of the piston
p1 = F / A
p1 = F / (π/4 * d^2)
p1 = 19094 / (π/4 * 0.47^2) = 110055 Pa = 110.055 kPa
variation of gravitational potential energy is defined as
ΔEp = m * g * Δh
ΔEp = 150 * 9.813 * 0.83 = 1222 J
Answer:
The critical depth of the rectangular channel is approximately 1.790 meters.
The flow velocity in the rectangular channel is 4.190 meters per second.
Explanation:
From Open Channel Theory we know that critical depth of the rectangular channel (), measured in meters, is calculated by using this equation:
(Eq. 1)
Where:
- Volume flow rate, measured in cubic meters per second.
- Gravitational acceleration, measured in meters per square second.
- Channel width, measured in meters.
If we know that ,
and
, then the critical depth is:
The critical depth of the rectangular channel is approximately 1.790 meters.
Lastly, the flow velocity (), measured in meters, is obtained from this formula:
(Eq. 2)
If we know that ,
and
, then the flow velocity in the rectangular channel is:
The flow velocity in the rectangular channel is 4.190 meters per second.
Answer:
(iv) second law of thermodynamics
Explanation:
The Clausius inequality expresses the second law of thermodynamics it applies to the real engine cycle.It is defined as the cycle integral of change in entropy of a reversible system is zero. It is nothing but mathematical form of second law of thermodynamics . It also states that for irreversible process the cyclic integral of change in entropy is less than zero
Answer:
// This program is written in C++ programming language
// Comments are used for explanatory purpose
/* The aim of this program is to to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. */
// Program starts here
#include <stdio.h>
#include<iostream>
using namespace std;
int main()
{
// Declare Variable of 100 characters
char word[100];
// Prompt user for input
cout<<"Your input goes here (max, 100 characters)";
cin>>word;
// Iterate through string to check for non alphabetic characters
for (int i = 0; word[i] != '\0'; ++i) {
// Check for uppercase and lowercase letters
while (!((word[i] >= 'a' && word[i] <= 'z') || (word[i] >= 'A' && word[i] <= 'Z') || word[i] == '\0')) {
for (int j = i; word[j] != '\0'; ++j) {
word[j] = word[j + 1];
}
word[j] = '\0';
}
}
cout<<"The resulting compressed string: "<<word;
return 0;
}
Answer:
w = str(input("input your values: "))
values = ' '.join(filter(str.isalpha, w))
while len(w) < 100:
print(values)
break
Explanation:
The code is written in python
w = str(input("input your values: "))
This code ask the user to input any string values with characters, numbers, line spaces , letters etc.
values = ' '.join(filter(str.isalpha, w))
This code filters the inputted value to bring only letters. All the letter are then joined together
while len(w) < 100:
The code check if the inputted value is less than 100 characters. While it is less than 100 characters. If it is less than 100 character the next code will function.
print(values)
This code prints the joined letters after checking with a while loop to confirm the length of character is less than 100
break
The break function breaks the code whether it print the values or not.
Generally, the letters will only be printed if the character inputted is less than 100 and later break the while loop or will not print any letter if the character is greater than 100 and later break.
b. A rigid bar does not bend regardless of the loads acting upon it.
c. A rigid bar deforms when experiencing applied loads.
d. A rigid bar is unable to translate or rotate about a support.
e. A rigid bar represents an object that does not experience deformation of any kind.
Answer:
option b and E are true
Explanation:
A lever is an example of a rigid bar that can rotate around a given point. In a rigid material, the existing distance does not change whenever any load is placed on it. In such a material, there can be no deformation whatsoever. Wit this explanation in mind:
option a is incorrect, given that we already learnt that no deformation of any kind happens in a rigid bar.
option b is true. A rigid bar remains unchanged regardless of the load that it carries.
option c is incorrect, a rigid bar does not deform with loads on it
option d is incorrect. A lever is a type of rigid bar, a rigid bar can rotate around a support.
option e is true. A rigid bar would not experience any deformation whatsoever.
A. The heat transfer rate from natural gas is 2105.26 MW
B. The heat transfer rate to river is 1305.26 MW
Efficiency = (power output / power input) × 100
Power input = Power input / efficiency
Power input = 800 / 38%
Power input = 800 / 0.38
Power input = 2105.26 MW
Thus, the heat transfer from natural gas is 2105.26 MW
Heat to the river = 2105.26 – 800
Heat to the river = 1305.26 MW
Learn more about efficiency:
Answer:
heat transfer from natural gas is 2105.26 MW
heat transfer to river is 1305.26 MW
Explanation:
given data
power output Wn = 800 MW
efficiency = 38%
solution
we know that efficiency is express as
......................1
put here value we get
38% =
Qin = 2105.26 MW
so heat supply is 2105.26
so we can say
Wn = Qin - Qout
800 = 2105.26 - Qout
Qout = 2105.26 - 800
Qout = 1305.26 MW
so heat transfer from natural gas is 2105.26 MW
and heat transfer to river is 1305.26 MW