Carla walked 5/6 of a mile last weekend, she walked 1/3 as far this weekend.how many miles did carla walk this weekend?

Answers

Answer 1

Answer: To do this multiply the fractions. Multiply the fractions because she walked 1/3 as far as last weekend, so she walked 1/3 of what she walked, and multiplying will help you find the answer.
5*1=5
6*3=18
5/18 is the answer

Answer 2

Answer: To do this, first convert 1 mile to 5280 ft to make it easier. Now to find 5/6 of 5280 (remember 'of ' means to multiply) turn 5/6 into .833333 (3 repeating) and multiply that by 5280 to get 4400. That means last weekend Carla walked 4400 ft. Now to find what she walked this weekend, turn 1/3 into .33333 (3 repeating) and multiply that by 4400. You should get 1466.6666 ( 6 repeating) or 1466 and 2/3 ft as the distance Carla walked this weekend.

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Using a transit, a surveyor measures the angle between two trees to be 111 degrees. If the first tree is 62 feet from the transit and the second tree is 58 feet from the transit, what is the distance between the two trees?

Answers

Answer:

The distance between the two trees is $98.92\ ft$

Step-by-step explanation:

we know that

Applying the law of cosines

$c^(2)=a^(2) +b^(2) -2(a)(b)cos (C)$

where

c -----> is the distance between the two trees

a ----> is the distance between the transit and the first tree

b ----> is the distance between the transit and the second tree

we have

$a=62\ ft$

$b=58\ ft$

$C=111\°$

substitute and solve for c

$c^(2)=62^(2) +58^(2) -2(62)(58)cos (111\°)$

$c^(2)=9,785.38$

$c=98.92\ ft$

randy Driven 54 miles he consumed 2 gallons of gas.So If he consumed 4 gallons of gas how many miles did he drive

Answers

Twice more! 108 gallons of gas

Divide 54 by 2 and then Multiply by 4 ☺️

There were 3,905 more hits on the school website in January than February. February had 9,854 hits. About how many hits did the website have during January and February?

Answers

9,854
-
3,905
_____
5,949

It is actually 5,940 because the equation asked about how many hits did the website have. Therefore, you have to round.

Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator

Answers

For this case we have the following expression:

$\frac {3} {\sqrt {17} - \sqrt {2}}$

We must rationalize the expression, so we multiply by:

$\frac {\sqrt {17} + \sqrt {2}} {\sqrt {17} + \sqrt {2}}$

So, we have:

$\frac {3} {\sqrt {17} - \sqrt {2}} * \frac {\sqrt {17} + \sqrt {2}} {\sqrt {17} + \sqrt {2}} =\n\frac {3 (\sqrt {17} + \sqrt {2}} {17- \sqrt {17} * \sqrt {2} + \sqrt {17} * \sqrt {2} -2} =\n\frac {3 (\sqrt {17} + \sqrt {2}} {15}$

Thus, the correct option is option B.

Answer:

OPTION B

Answer:

Step-by-step explanation:

To simplify something that looks like $\frac{\text{whatever}}{√(a)-√(b)}$ you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

$√(a)+√(b)$ .

If you had $\frac{\text{whatever}}{√(a)+√(b)}$ , then you would multiply top and bottom the conjugate of $√(a)+√(b)$ which is $√(a)-√(b)$ .

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens. The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First: a(a)=a^2

Outer: a(-b)=-ab

Inner: b(a)=ab

Last: b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of $√(17)-√(2)$ is

$√(17)+√(2)$ .

This is the thing we are multiplying and top and bottom.

What are all the powers of 3 through 1000

Answers

3 to the 1st is 3
3 to the 2nd is 9
3 to the 3rd is 27
3 to the 4th is 81
3 to the 5th is 243
3 to the 6th is 729

A sequence is defined recursively by f(1) = 16 and f(n) = 3f(n-1) +2. Find f(4)

Answers

If you would like to find f(4), you can calculate this using the following steps:

f(1) = 16
f(n) = 3 * f(n-1) + 2
f(2) = 3 * f(2-1) + 2 = 3 * f(1) + 2 = 3 * 16 + 2 = 48 + 2 = 50
f(3) = 3 * f(3-1) + 2 = 3 * f(2) + 2 = 3 * 50 + 2 = 152
f(4) = 3 * f(4-1) + 2 = 3 * f(3) + 2 = 3 * 152 + 2 = 458

The correct result would be f(4) = 458.

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