The confidence interval of the given statistics when calculated with the given parameters is; (49.1 minutes to 59.3 minutes)
Formula for Margin of error is;
M = z * σ/√n
We are given;
Sample size; n = 50
mean; x' = 54.2 minutes
standard deviation; σ = 14.0 minutes
z-score = 2.58
Thus;
M = 2.58 × (14/√50)
M = 5.11
Confidence interval is;
CI = x' ± M
CI = (54.2 + 5.1), (54.2 - 5.1)
CI = (49.1 minutes, 59.3 minutes)
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Answer:
-1 4/5
Step-by-step explanation:
In mathematics, a fraction is a number that represents a part of a whole. It consists of a numerator and a denominator. The numerator represents the number of equal parts of a whole, while the denominator is the total number of parts that make up said whole. For example, in the fraction 3 5, the numerator is 3, and the denominator is 5. A more illustrative example could involve a pie with 8 slices. 1 of those 8 slices would constitute the numerator of a fraction, while the total of 8 slices that comprises the whole pie would be the denominator. If a person were to eat 3 slices, the remaining fraction of the pie would therefore be 5 8 as shown in the image to the right. Note that the denominator of a fraction cannot be 0, as it would make the fraction undefined. Fractions can undergo many different operations, some of which are mentioned below.
Answer:
181
Step-by-step explanation:
Area of a semicircle: 1/2 (pi • r^2)
1/2(3.14 • 100)
1/2 ( 314 )
157
Triangle:
(6 • 8) ÷ 2
48 ÷ 2
24
Add the area of the triangle & semicircle together: 157 + 24 = 181
Hope this helps! Have a great day!
Step-by-step explanation:
To make the function f(x) = {sin(1/x), x ≠ 0; k, x = 0} continuous at x = 0, we need to find the value of k that ensures the limit of f(x) as x approaches 0 exists and is equal to k.
First, let's find the limit of sin(1/x) as x approaches 0:
lim(x -> 0) sin(1/x)
This limit does not exist because sin(1/x) oscillates wildly as x gets closer to 0. Therefore, in order for the function to be continuous at x = 0, we need to choose k such that it compensates for the oscillations of sin(1/x) as x approaches 0.
A suitable choice for k is 0 because the limit of sin(1/x) as x approaches 0 is undefined, and setting k = 0 ensures that f(x) becomes a continuous function at x = 0.
So, the correct choice is:
d. None (k = 0)
The value of k that would make the function f(x) = sin(1/x) when x ≠0 and f(x) = k when x=0 continuous at x=0 doesn't exist. This is because the limit of sin(1/x) as x approaches 0 is undefined, hence the function cannot be made continuous at x = 0 for any value of k.
To find the value of k that makes the function continuous at x=0, we can apply the definition of continuity, which states that a function, f(x), is continuous at a certain point, x0, if three conditions are met:
In the case of the function f(x) = sin(1/x), the value for x = 0 is undefined, but we've been given that f(0) = k. To make the function continuous at x = 0, the value of k should ideally be equal to the limit of sin(1/x) as x approaches 0.
However, as x approaches 0, sin(1/x) oscillates between -1 and 1, making the limit non-existent. Because the limit does not exist, the function is not continuous at x=0 no matter the chosen value of k. Therefore, the correct answer is (d) None.
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Remark
This requires some sort of constant that each of the ratio members is multiplied by.
Call the constant x
Equation
2x + 3x + 7x = 90 Add the left hand side
Solution
12x = 90 Divide by 13
x = 90 /12
x = 7,5
Answer
2x = 2 * 7.5
2x = 15
3x = 22.5
7x = 52.5
Sum = 90 as it should be