Rewrite the original equation as:
Log(4x^2) - log(3yz)
Rewrite log(4x^2) as log(4) + log(x^2)
Rewrite log(4) as 2log(2)
Rewrite log(x^2) as 2log(x)
Separate log(3yz) into 3 logs: log(3), log(y) and log(z)
Now combine them to get:
2log(2) + 2log(x) - log(3) - log(y) - log(z)
The decomposition of the logarithmic expression Log((4)/(3yz)) leads to the end result: Log(4) + Log() - Log(3) - Log(y) - Log(z). The given expression is separated into individual logarithms applying the logarithmic rules.
The decomposition of the logarithmic expression Log((4x2)/(3yz)) according to the laws of logarithms can be done as follows:
Using the rule that log(a/b) = log(a) - log(b), we can first split the expression into two parts: Log(4x2) - Log(3yz).
From there, we can apply the rule that log(ab) = log(a) + log(b) to split these further. So, Log(4x2) becomes Log(4) + Log(x2), and Log(3yz) becomes Log(3) + Log(y) + Log(z).
Finally, we substitute these back into the original expression to get the final decomposition: Log(4) + Log(x2) - Log(3) - Log(y) - Log(z).
#SPJ12
Answer:
negative 70 (-70)
Step-by-step explanation:
below sea level, so below zero, would be -70
Answer:
-70
Step-by-step explanation:
Its below it would be in the negatives
Answer:
a or b
Step-by-step explanation:
Answer:
B. 30
Step-by-step explanation:
3/4 = .75
120 * .75 = 90
Of those 90 students 1/3 wore sandals.
1/3 = approximately .33
90 * .33 = 29.7
Therefore, around 30 students wore jeans and sandals.
Answer:
f(n+1)=f(n)-99.4
Step-by-step explanation:
We are given a sequence as:
99.4,0,-99.4,-198.8, and so on
We can see that the sequence is constantly getting decreased by -99.4
i.e. f(1)=99.4
Then, f(2)=f(1)-99.4
=99.4-99.4
=0
f(3)=f(2)-99.4
=0-99.4
=-99.4
Hence, the recursive formula is:
f(n+1)=f(n)-99.4
Answer:
Step-by-step explanation:
Given,
Art electives = 3,
History electives = 4,
Computer electives = 5,
Total number of electives = 3 + 4 + 5 = 12,
Since, if a student chooses an art elective and a history elective,
So, the total combination of choosing an art elective and a history elective =
Also, the total combination of choosing any 2 subjects out of 12 subjects =
Hence, the probability that a student chooses an art elective and a history elective =
Which is the required expression.
Answer: Hello!
we have:
3 art electives
4 history electives
5 computer electives
which adds to a total of 12.
If the selection is random, each elective has the same probability.
The probability of selecting an art electives is the quotient between the number of art electives and the total number of electives:
3/12
suppose that this event is true, now we need to see the probability of choosing also a history elective;
We do the same process as before, we have 4 history electives and, because we already selected 1 in the previous step, we have a total of 11 electives:
the probability now is 4/11.
Now we want to calculate the joint probability of bot events is equal to the product of their probabilities; this is:
p= (3/12)*(4/12) = (4*3)/(11*12) = 12/(11*12) = 1/11
But there is also the case where the selection is in the other order (first history and second art) so the probability is equal to
2*1/11 = 2/11
Answer:
b) RH = UM = HM = RU Reason: Since they form a rhombus, its sides are of equal length.
c) RUBM is a rhombus Reason: Given
d) Reason: RUBM is identified as a rhombus. Thus, its sides are of equal length.
e) RUMH and RUBM are rhombus which have similar dimensions. Each sides of any rhombus is equal in length and since both are of similar dimensions, then, all of their sides lengths are equal with each other.
f) Rhombus have opposite sides that are parallel and its opposite angles are equal. Rhombus is also called a parallelogram.