What is the quotient of 32 divided by -4 as a fraction?

Answers

Answer 1

Answer: the neat part of dividing and putting them into fraction form is that you just put those two numbers together in a fraction

32/4(32 divided by 4)

however, this can be simplified into 8/1 or just 8 but the question asks us to state it as a fraction so you can either leave it as 32/4 or 8/1.

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In the spinner below the large wedges are twice the size of the smaller ones. What is true about the probablilty of landing on 6 and the probability of landing on 5

Answers

Answer:

we need an image of the spinner to answer the question. are we supposed to just know what it looks like?

Step-by-step explanation:

flvs she cheating

33 1/3 percent of 600

Answers

$33(1)/(3)$ × $(1)/(100)$ = $(1)/(3)$
To change percent to fraction/decimal
$(1)/(3)$ ×600=200
Answer: 200

331/3 of 600 331/3×600 100/3×1/600. 1/12×100 =81/3%

Which of the following is equivalent to the expression below? 9^10*9^x

Answers

Answer:

Step-by-step explanation:

$a^(m)*a^(n)=a^(m+n)\n\n9^(10)*9^(x)=9^(10+x)$

In exponent multiplication, if the bases are same then add the exponents.

$\small \sf \leadsto 9 {}^(10 +x)$

Step-by-step explanation:

Using exponent's product rule

$\small \sf \: x {}^(n) * x {}^(m) = x {}^(n + m)$

$\small \sf \leadsto \: 9 {}^(10) * 9 {}^(x)$

$\small \sf \leadsto 9 {}^(10 + x)$

Find the volume of the largest sphere that could be enclosed in a cube with a side length of 10 cm. Round to the nearest tenth.

Answers

$Look\ at\ he\ picture.\n\nR=5cm\n\nV=(4)/(3)\pi R^3\n\nV=(4)/(3)\pi\cdot5^3=(4)/(3)\pi\cdot125=(500)/(3)\pi\approx(500)/(3)\cdot3.14\approx523.3\ (cm^3)$

Calculate the marked price of a sweater purchased at Rs. 1075 allowing 14% discount. ( please do proper answer )

Answers

Answer:

Rs. 1250

Step-by-step explanation:

Let the marked price be x, then we have:

x - 14% = 1075
x*(100 - 14)/100 = 1075
x*0.86= 1075
x = 1075/0.86
x = 1250

Marked price was Rs. 1250

Please I really need help with this question it’s due tomorrow!!

Answers

Answer:

THERE

Step-by-step explanation:

a) To determine how far each ostrich ran, we need to calculate the area under the velocity-time graph for each ostrich. Since the graph represents velocity, the area under the graph represents the distance traveled.

For Ostrich Bert:

The area under the graph can be divided into two sections: a triangle and a rectangle. The triangle's base is 3 seconds and its height is 18 m/s, so its area is (1/2) * 3 * 18 = 27 m. The rectangle has a base of 2 seconds and a height of 9 m/s, so its area is 2 * 9 = 18 m. Adding the areas together, Bert ran a total distance of 27 + 18 = 45 meters.

For Ostrich Ernie:

The area under the graph can also be divided into two sections: a triangle and a rectangle. The triangle's base is 4 seconds and its height is 12 m/s, so its area is (1/2) * 4 * 12 = 24 m. The rectangle has a base of 2 seconds and a height of 6 m/s, so its area is 2 * 6 = 12 m. Adding the areas together, Ernie ran a total distance of 24 + 12 = 36 meters.

b) To calculate the average velocity of Bert, we need to divide the total distance he ran (45 meters) by the total time it took (5 seconds). Therefore, Bert's average velocity is 45 meters / 5 seconds = 9 m/s.

c) The initial acceleration of Ernie can be determined by finding the slope of the velocity-time graph during the initial portion. From the graph, we can see that Ernie's velocity increases by 6 m/s over the first 2 seconds. Therefore, his initial acceleration is (change in velocity) / (change in time) = 6 m/s / 2 seconds = 3 m/s^2.

d) Without further calculation, we can determine that Ernie had the greatest initial acceleration. This is because Ernie's velocity increases at a steeper slope during the initial part of the graph compared to Bert's velocity. The greater the slope, the greater the acceleration. Therefore, Ernie had the greatest initial acceleration.

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