Answer:
Therefore, Option 3rd is correct that is which is required equation of a line.
Step-by-step explanation:
We have given a point through which line is passing that is (7,-2) and slope is also given which is -3
We have a general equation of line which is
Here,
And on substituting the values in the given formula for equation of a line we will get
Therefore, Option 3rd is correct that is which is required equation of a line.
a. 644
b. 690
c. 15,341
d. 29
the answer is b. 690
Answer: He will not have enough room
Step-by-step explanation: To determine if Andrew has enough room for his 250 CDs on the two shelves inside the bookcase, we need to calculate how many CD racks can fit on each shelf and how many CDs each of these racks can hold.
The bookcase is 3 ft wide, which is equivalent to 36 inches. Each shelf is 15 inches high. Therefore, the available space for CD racks on each shelf is 36 inches in width and 15 inches in height.
Each CD rack is 17 inches wide and 7 inches high. To calculate how many racks can fit on each shelf, we can use the following formula:
Number of racks on a shelf = (Width of shelf) / (Width of CD rack)
Number of racks on a shelf = 36 inches / 17 inches ≈ 2.12 (round down to 2, as you can't have a fraction of a rack)
Now, let's calculate how many CDs each of these racks can hold. Each CD rack can hold three stacks of 12 CDs each, for a total of 3 x 12 = 36 CDs.
So, on each shelf, Andrew can fit 2 CD racks, and each rack can hold 36 CDs. Therefore, each shelf can store 2 x 36 = 72 CDs.
Since Andrew has two shelves, he can store a total of 2 x 72 = 144 CDs in the bookcase.
So, he will be able to store 144 CDs in the bookcase, which is less than his 250 CDs. Therefore, he won't have enough room for all his 250 CDs in the bookcase, and he will need additional storage for the remaining CDs.
The complex number 5-3i is plotted on the complex plane at point (5,-3). The modulus of this complex number is approximately 5.8.
Complex numbers are mathematical entities that extend real numbers to include imaginary components, represented as "a + bi," where 'a' and 'b' are real numbers and 'i' is the imaginary unit (equal to the square root of -1). Complex numbers are used in various fields, including engineering and physics, to describe phenomena involving oscillations, electrical circuits, and quantum mechanics. They are vital for solving equations that have no real solutions and play a fundamental role in understanding complex systems and mathematical analysis, making them a valuable tool in science and engineering.
To graph the complex number 5-3i in the complex plane, you need to plot the point (5,-3). On the horizontal axis (real axis) you mark 5 and on the vertical axis (imaginary axis) you mark -3.
The modulus of a complex number a + bi is the square root of (a2 + b2). In this case, the modulus would be sqrt((5)2 + (-3)2) = sqrt(25 + 9) = sqrt(34), which is approximately 5.8 when rounded to the nearest tenth.
Learn more about Complex Numbers here:
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Given :
Sugar required for 2 1/2 = 5/2 dozen of cookies is 1 1/4 = 5/4 cups.
To Find :
How many cups of sugar does she need to make the cookies for her party.
Solution :
Let, cups of sugar required to make cookies for her party is x.
So,
Therefore, 1/2 cup of cookies is required to make 1 dozen cookies.
Hence, this is the required solution.
Answer: 25/8
Step-by-step explanation:
We would first turn 2 1/2 and 1 1/4 into an improper fraction.
That leaves us with 5/2 and 5/4.
Then, because she needs to make 5/2 dozen cookies and needs 5/4 cups of sugar for every batch, we would multiply 5/2 and 5/4 together.
Therefore x, or the amount of sugar she needs, is 25/8
table?
Answer:
A. y-1=5/3(x-3)
Step-by-step explanation:
please look at the graph in my pic to see my answer is correct
hope it helps :)