My mum was 27 when I was born. 8 years ago she was twice as old as I shall be in 5 years time. How old am I now?

Answers

Answer 1

Answer: use timeline and work from NOW
me. mom
(1) @born 0. 27
My mum was 27 when I was born.
(2) now-8. x-8. y-8
(3) now. x y
(4) now+5. x+5. y+5

(1)&(3). y-x = 27-0 = 27

8 years ago she was twice as old as I shall be in 5 years time.
(2)&(4). y-8 = 2(x+5)

2 variables 2 equations ... solve x
x = 9, y = 36

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A game has a rectangular board with an area of 44 in2. There is a square hole near the top of the game board in which you must not toss in a bean bag. The square has side lengths of 3 in. What is the probability of not tossing the bag through the hole?A)9/44
B)3/9
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D)35/44

Answers

A. 9/44 idk if it is the right anwser but good
Luck

84-63i in conjugate form?.

Answers

Conjugate form of complex number:
z = a + b i is a - b i
and for : z = a - b i is : a + b i
Conjugate form of 84 - 63 i is : 84 + 63 i

Write 8 19/20 as a decimal.

Answers

Answer:

8.95

Step-by-step explanation:

Since 8 is a whole number it’s before the decimal. So,

To turn a fraction to a decimal just divide the top number by the bottom. So,

19/20 = 0.95

8 + 0.95 = 8.95

Therefore, the answer is 8.95

Answer:

8.95

Step-by-step explanation:

$8(19)/(20) = (179)/(20)$
179 ÷ 20 = 8.95

I hope this helps!

How do i do problems that have fractions and a negative or a zero exponent with it?

Answers

Remember these:
$\left((a)/(b)\right)^(-c)=\left((b)/(a)\right)^(c)\n\na^0=1$

The number 248,682 rounded off to the nearest hundreds becomes A. 248,700.
B. 248,680.
C. 249,000.
D. 250,000.

Answers

A. 248,700
_
7 is in the hundreth place.

B. 248,680.
8 is in the hundredth place, because
6 is the tenth place

Can you solve (4x-3)/(x+2)+(15)/(x-3)

Answers

Please see the pic, I'd solved in it.

$(4x-3)/(x+2)$ + $(15)/(x-3)$ = 0
1st step: We need to have a common denominator.
So we do this:
$((4x-3)*(x-3))/((x+2)*(x-3))$ + $((15)*(x+2))/((x-3)*(x+2))$ = 0
2nd step: Distribute them
$(4x^(2)-3x-12x+9)/((x-3)(x+2))$ + $(15x+30)/((x+2)(x-3))$ = 0
3rd step: Do the rest of the equation!
We can put it on one fraction, its fine.
$(4x^2-15x+9+15x+30)/((x+2)(x-3))$ = 0
$(4x^2+39)/((x+2)(x-3))$ = 0 (-15 and 15 cancels out)
4th step: take the denominator to the other side
4x²+39 = 0 (anything × 0 = 0)
5th step: Take 39 to the other side
4x² = -39
6th step: Divide by 4 on both sides
$(4x^2)/(4)$ = $-(39)/(4)$
(4 and 4 cancels out)
x² = $-(39)/(4)$
7th step: Take the square root to keep x alone
x = $-\sqrt(39)/(4)$
It can also be written as:
x = $-( √(39) )/( √(4) )$
Final answer:
x = $-( √(39) )/(2)$

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