Answer:
11 m/s
Explanation:
wave in medium A, the wave in medium B has
(1) half the speed
(2) twice the speed
(3) half the frequency
(4) twice the frequency
The situation described in the question pertains to wave propagation. Given that wave speed in a given medium is constant, and the relationship between wave speed, wavelength, and frequency, the wave in medium B, which has double the wavelength of the wave in medium A, would have half the frequency of the wave in medium A.
This question is about wave propagation between two different mediums, labeled 'A' and 'B'. The fundamental principle involved here is the dependence of wave speed on the medium through which it travels. However, it's necessary to recognize that wave speed also depends on wavelength and frequency. This relationship is encapsulated by the formula v = fλ, where v is wave speed, f is frequency, and λ is wavelength.
From the problem statement, we understand that the wavelength doubles when going from medium A to medium B. We are then asked to deduce the corresponding change in wave speed or frequency. If the wavelength doubles and the wave speed remains the same, the only possible adjustment is for the frequency to halve. So, the wave in medium B, compared to the wave in medium A, would have half the frequency (3). This is because wave speed in a given medium is constant and as per the formula, if wavelength increases, frequency must decrease.
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