Help please!
Answer:
CP = 6
Step-by-step explanation:
The length of segment BC is given by the Pythagorean theorem:
AC² = AB² +BC²
(√61)² = 5² + BC² . . . . . fill in the given numbers
61 -25 = BC² = 36 . . . . .subtract 25
BC = 6 . . . . . . . . . . . . . . take the square root
Since the center of the circle is on AB and is tangent to BC, it must pass through point B. That is, segment BC of length 6 is one of the tangent lines from point C. The other one, to point P, must be the same length, so ...
CP = 6
The equation the line is y = -2x/3 + 28/3
Given that are two points we need to find the equation of a line passing through it,
(5, 6) and (8, 4)
We know that an equation of line passing through two points (x₁, y₁) and (x₂, y₂) is given by =
y - y₁ = y₂-y₁ / x₂-x₁ (x-x₁)
Here (x₁, y₁) and (x₂, y₂) = (5, 6) and (8, 4)
y - 6 = 4-6 / 8-5 (x-5)
y - 6 = -2/3 (x-5)
y = -2/3 (x-5) + 6
y = -2x/3 + 10/3 + 6
y = -2x/3 + 28/3
Hence the equation the line is y = -2x/3 + 28/3
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Answer ASAP plz
Answer: The answer is -1
Step-by-step explanation:
-4(y - 2) = 12
-4y + 8 = 12
- 8 - 8
_____________
-4y = 4
________
-4 -4
y = -1
Answer:
then what?
Step-by-step explanation: