A school is building a rectangular soccer field that has an area of 6000 yards. The soccer field must be 40 yards longer than it's worth. Determine algebraically the dimensions of the soccer field, in yards. Show/ explain work

Answers

Answer 1

Answer: Given, soccer field length is 40 m longer than width
lets consider width=w
so, length = w+40
area = length*width=6000
(w+40)*w=6000
w^2 +40*w-6000=0;
w^2+(100*w-60*w) -6000=0
(w^2 + 100*w) - (60*w+6000)=0
w(w+100)-60(w+100)=0
(w+100)(w-60)=0
w=60, because width will not be '-100'
w=60 and L=60+40=100

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Answers

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To find the length of segment AB on a coordinate plane, you can use the distance formula.

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Learn more about Coordinate plane here:

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$({ 7v}^(2) )$
write your answer without parentheses

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$7v^(2)$
It is actually correct

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Well if you take 6x7 you get 42. If each windmill has 6 blades on it and there are 7 windmills you just take those two numbers and multiply them.

A school photography company allows parents to purchase fractions of portrait packages. Parents can select only the pictures they want, and return a fraction of package. The company tracks the fraction of each returned package. The company loses money on any package returned with more than of the pictures. On what fraction of the packages did the company lose money?

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Answers

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