If you went to the moon, how would your mass change relative to your mass on Earth?It would be the same on the moon as on Earth

It would increase because of less gravity

It would decrease because of less gravity

None of the above

Answers

Answer 1

Answer:

Answer:

Explanation:

you are on the moon or on Earth. Mass is an intrinsic property of matter and is a measure of the amount of matter in an object. It does not depend on the location of the object or the gravitational field it is in. Therefore, your mass would be the same on the moon as it is on Earth.

It would be the same on the moon as on Earth

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How are evaporation and condensation alike

Answers

well,condensation is more like gas becoming liquid or solid while evaporation is liquid becoming gas.

the thing those two have in common is that they have been gas or are gas.

Condensation changes gas to solid/liquid. Evaporation turns liquid into gas

The accepted value for the percent by mass of water in a hydrate is 36.0%. In a laboratory activity, a student determined the percent by mass of water in the hydrate to be 37.8%. What is the percent error for the student's measured value?(1) 5.0% (3) 1.8%

(2) 4.8% (4) 0.05%

Answers

The original or accepted value for the percent by mass of water in a hydrate = 36%
Percen by mass of water in the hydrate determined by the student
in the laboratory = 37.8%
So the difference between the actual and the percent by mass in water determined by student = (37.8 - 36.0)%
   = 1.8%
So the percentage of error made by the student = (1.8/36) * 100 percent
   = (18/360) * 100 percent
   = ( 1/20) * 100 percent
      = 5 percent
So the student makes an error of 5%. Option "1" is the correct option.

Answer:

Explanation:

Why does the density of a substance remain the same for different amounts of the substance?

Answers

Density represents mass per volume and so when homogeneous and incompressible, an amount increase/decrease does not affect density, as the mass and volume change in the same amount. Hope this helps!

What is the definition of a Lewis base?a substance that donates a proton
a substance that donates electrons to form a covalent bond
a substance that accepts electrons to form a covalent bond
a substance that when dissolved in water increases hydrogen ion concentration

Answers

The definition of a Lewis base is: C. a substance that accepts electrons to form a covalent bond.

What is a Lewis base?

A Lewis base can be defined as a specie of an ionic or chemical compound that contains an empty orbital which allows it to donate an electron pair (two or more electrons) to form a covalent bond.

This ultimately implies that, a Lewis base is a chemical substance that accepts an electron pair (two or more electrons) to form a covalent bond.

Examples of a Lewis base.

In Chemistry, some examples of a Lewis base include the following:

$OH^-$

$H_2O$

$NH_3$

Read more on Lewis base here: brainly.com/question/3655338

Answer:

the definition is : a compound or ionic species which can donate an electron pair to an acceptor compound.

so as far as i know i know the answer is: a substance that accepts electrons to form a covalent bond.

please mark me brainliest may god bless you...

Explanation:

Describe the three forces thought to move tectonic plates

Answers

Convection
Ridge Push
Slab Pull

Wind, water (erosion) the liquid in the mantle ie:molten rock

Consider the half reactions below for a chemical reaction.Mg— Mg2(aq) + 2e-
2H* (aq) + 2e--> H2(g)
What is the overall equation for this chemical reaction?
Mg(s)+2H+ (aq) — Mg2+ (aq) + H2(
Mg(s) + 2H+ (aq) —> Mg2+ (aq) + 2e-
Mg2+ (aq)+H2(9)—> Mg(s)+ 2H+ (aq)
Mg(s)+2H--> Mg(aq) + H2(g)

Answers

Answer:

Explanation:

The half reactions are:

Mg $_(s)$ → Mg²⁺ $_(aq)$ + 2e⁻

2H⁺ $_(aq)$ + 2e⁻ → H₂ $_(g)$

The first equation is an oxidation half while the second is a reduction half. To get the overall reaction equation, we simply combine the two equations. The reactants combines at the left hand side with the products comes together at the right hand side.

Mg $_(s)$ + 2H⁺ $_(aq)$ + 2e⁻ → Mg²⁺ $_(aq)$ + 2e⁻ + H₂ $_(g)$

Now we cancel out the species that appear on both sides:

Mg $_(s)$ + 2H⁺ $_(aq)$ → Mg²⁺ $_(aq)$ + H₂ $_(g)$

Answer:answer is A on edg

Explanation:

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