By using a 2-meter stick (like the one in lab) marked in millimeters and a stopwatch that measures to 1/100h of a second, you decide to measure the speed of a motorized toy car that travels at a constant velocity. You measure out a 162.0cm interval with the 2-meter stick and time how long it takes the car to travel that distance using the stopwatch. Repeating the ex 2.95 s Calculate the average speed of the toy car What are the absolute and relative uncertainties of the distance and time measurements? Which measurement is more uncertain? Use the weakest link rule to determine the relative and absolute uncertainty in your speed estimation. Explain why it is necessary to calculate relative uncertainties. Why is absolute uncertainty not enougn ent 5 times you get the following time data: 3.11 s 3.15 s 2.84 s 2.97 s
Answers
Answer:
Explanation:
The average speed of a body is defined as the ratio between total distance and total time
v = dx / dt
v = 162.0 / 2.95
v = 54.9 m / s
The absolute errors (uncertainties) of the distance and time measurements as measured with instruments are the errors of the instruments
Δx = 0.1 cm
Δt = 0.01 s
Relative errors (uncertainties) are the absolute errors between the measured value
Er = Δx /x
Er = 0.1 / 162.0
Er = 6.2 10⁻⁴ length
Er = 0.01 / 2.95
Er = 3.4 10⁻³ time
The most uncertain measure is the time to have a greater relative error
Let's calculate the relative speed error
Δv / v = dv / dx dx + dv / dt dt
dv / dx = 1 / t
dv / dt = x (-1 / t²)
Er = Δv / v = 1 / t Δx + x / t² Δt
Er = 0.1 / 2.95 + 162.0/2.95² 0.01
Er = 0.034 + 0.19
Er = 0.22
We can observe that the relative error of time is much higher than the relative error of distance, so to reduce the speed error, time must be measured with much more precision
Absolut mistake
Er = Δv / v
Δv = Er v
Δv = 0.22 54.9
Δv = 12 cm / s
v± Δv = (5 ±1 ) 10 cm/s
When calculating the relative uncertainty, it is known which magnitude should be more precisely medical to reduce the total error of a derived magnitude
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What is suedo force.
Answers
The value of final angular speed of the uniform rod which rests on the frictionless horizontal surface is,
What is angular speed of a body?
The angular speed of a body is the rate by which the body changed its angle with respect to the time. It can be given as,
A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.
The rod is initially at rest. A bullet traveling parallel to the horizontal surface and perpendicular to the rod with speed v strikes the rod at its center and becomes embedded in it.
The mass of the bullet is one-fourth the mass of the rod. The diagram for the above condition is attached below.
In the attached image the angular momentum about the point A is constant just before and after the collision. Thus,
Put the value of inertia as,
Solving it further we get,
Hence, the value of final angular speed of the uniform rodwhich rests on the frictionless horizontal surface is,
Learn more about the angular speed here;
Answer: a) 0.315 (V/L)
Explanation:
From Conservation of angular momentum, we know that
L1 = L2 ,
Therefore MV L/2 = ( Irod + Ib) x W
M/4 x V x L/2 = (M (L/2)^2 + 1/3xMxL^2) x W
M/8 X VL = (ML^2/16 + ML^2 /3 )
After elimination we have,
V/8 = 19/48 x L x W
W = 48/8 x V/19L = 6/19 x V/L
Therefore W = (0.136)X V/L
Answers
The required force parallel to the incline to hold the monolith on this causeway will be "2.9 tons".
Angle and Force
According to the question,
Angle, a = 3.7 degrees or,
Sin a = 0.064
Force, F = 46 tons
We know the relation,
Parallel (tangential), = F Sin a
By substituting the values,
= 46 × 0.064
= 2.9 tons
Thus the response above is appropriate answer.
Find out more information about Force here:
Answer:
2.9tons
Explanation:
Note that On an incline of angle a from horizontal, the parallel and perpendicular components of a downward force F are:
parallel ("tangential"): F_t = F sin a
perpendicular ("normal"): F_n = F cos a
At a=3.7 degrees, sin a is about 0.064 and with F = 46tons:
F sin a ~~ (46 tons)*0.064 ~~ 2.9tons
Also see attached file
B. A pingpong ball rolling a 2 m/s
C. A bowling ball rolling at 1m/s
D. A car rolling at 5 m/s
Answers
Answer:
A. A tractor trailer rig moving at 2 m/s
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The inertia of an object such as a tractor trailer rig is greatly dependent or influenced by its mass; the higher quantity of matter in a tractor trailer rig, the greater will be its tendency to continuously remain at rest.
Hence, the object that has more inertia is a tractor trailer rig moving at 2 m/s because it has more mass than all the other objects in the category. Also, the mass of an object is directly proportional to its inertia.
Answers
Answer:
- 93.6 N in the 41° cable
- 155.6 N in the 63° cable
- 200 N in the vertical cable
Explanation:
Let T and U represent the tensions in the 41° and 63° cables, respectively. In order for the system to be stationary, the horizontal components of these tensions must balance, and the vertical components of these tensions must total 200 N.
Tcos(41°) =Ucos(63°) . . . . . balance of horizontal components
U = Tcos(41°)/cos(63°) . . . . write an expression for U
__
The vertical components must total 200 N, so we have ....
Tsin(41°) +Usin(63°) = 200
Tsin(41°) +Tcos(41°)sin(63°)/cos(63°) = 200
T(sin(41°)cos(63°) +cos(41°)sin(63°))/cos(63°) = 200
T = 200cos(63°)/sin(41° +63°) ≈ 93.6 . . . newtons
U = 200cos(41°)/sin(41° +63°) ≈ 155.6 . . . newtons
__
The vertical cable must have sufficient tension to balance the weight of the traffic light, so its tension is 200 N.
Then the tensions in the 3 cables are ...
41°: 93.6 N
63°: 155.6 N
90°: 200 N
The tension in each of the three cables are 94.29, 155.56 and 200 Newton respectively.
Given the following data:
- Force = 200 Newton.
- Angle 1 = 41°
- Angle 2 = 63°
How to calculate the tension.
First of all, we would determine the third tension force based on the vertical component as follows:
Next, we would apply Lami's theorem to resolve the forces acting on the traffic light at equilibrium:
For the horizontal component:
....equation 1.
For the vertical component:
...equation 2.
Substituting eqn. 1 into eqn. 2, we have:
For the first tension:
Read more on tension here: brainly.com/question/4080400
Answers
Answer:
True. A permanent magnet like the earth produces its own B field due to movement of the iron core. The earths magnetic field is the reason why we have an atmosphere and it also is the only defense against solar flares. A coil of wire or solenoid that has current have so much moving charge that the motion of the electrical charge can create a significant G b-field
Answers
Answer:
Lifetime = 4.928 x 10^-32 s
Explanation:
(1 / v2 – 1 / c2) x2 = T2
T2 = (1/ 297900000 – 1 / 90000000000000000) 0.0000013225
T2 = (3.357 x 10^-9 x 1.11 x 10^-17) 1.3225 x 10^-6
T2 = (3.726 x 10^-26) 1.3225 x 10^-6 = 4.928 x 10^-32 s
Final answer:
To find the proper lifetime of the particle, we can use the time dilation equation and the Lorentz factor. Plugging in the given values, we find that the proper lifetime of the particle is approximately 5.42 × 10^-9 seconds.
Explanation:
To find the proper lifetime of the particle, we can use the time dilation equation, which states that the proper time (time experienced in the frame of reference of the particle) is equal to the time observed in the laboratory frame of reference divided by the Lorentz factor. The Lorentz factor can be calculated using the equation γ = 1/√(1 - (v/c)^2), where v is the velocity of the particle and c is the speed of light. Given that the particle is moving at 0.993c, the Lorentz factor is approximately 22.82.
Next, we can use the equation Δx = βγcτ, where Δx is the length of the track, β is the velocity of the particle in units of the speed of light (v/c), γ is the Lorentz factor, c is the speed of light, and τ is the proper lifetime of the particle. Plugging in the given values, we have 1.15 mm = 0.993 * 22.82 * c * τ. Solving for τ, we find that the proper lifetime of the particle is approximately 5.42 × 10^-9 seconds.
Learn more about Proper lifetime of high-energy particles here:
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