b. increasing the pressure of the solution
c. decreasing the size of the salt particles
d. increasing the temperature of the solution
The following which would not affect the rate of dissolution of salt in a beaker of water is:
The dissolution of salt in a beaker of water increases when an external force stirs it which makes it move from its initial position to a new position.
As a result of this, we can see that if there is a decrease in the size of salt in the beaker of water, there would also be a change in the dissolution of salt in the water.
However, increasing the pressure of the solution would not affect the rate of dissolution of salt in the beaker of water.
Therefore, the correct answer is option B
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Answer: Option (b) is the correct answer.
Explanation:
When we stir a solution then its particles start to move from their initial position leading to more number of collisions between them.
As a result, rate of dissolution increases with stirring.
When we increase the pressure then no change in dissolution occurs because in liquids and solids pressure does not play any role is solubility or dissolution.
When we decrease the size of solute particles then there occurs an increase in surface area of solute. Hence, due to this more number of solute particles are able to come in contact with the solvent.
This will lead to more number of collisions. Therefore, rate of dissolution will increase.
Also, when we increase the temperature then molecules of solution will gain kinetic energy leading to more number of collisions which will eventually lead to increase in rate of dissolution.
Thus, we can conclude that out of the given options increasing the pressure of the solution would not affect the rate of dissolution of salt in a beaker of water.
a. True
b. False
Answer:
true
Explanation:
got it right on odyssey
B) Water would be able to dissolve all ionic compounds.
C) Water would not expand when it freezes.
D) Water would not exist on Earth.
The hydrogen bond is a secondary bond formed between a hydrogen (attached to an highly electronegative element ,: F, O or N) and another atom of an highly electronegative element ,: F, O or N.
In case of water hydrogen bond helps water
a) to dissolve certain substances which can make hydrogen bond
b) it makes it liquid and room temperature unlike H2S which is a gas at room temperature due to absence of hydrogen bond
c) higher volume and low density of ice as compared to liquid water. Due to hydrogen bond ice forms open cage like structure which increases its volume and decreases its density. Thus water expands on freezing
So in absence of hydrogen bond Water would not expand when it freezes.
c. a flask of pond water.
d. a jar of soil.
The sample that is a pure substance is:A. a test tube of zinc oxide.
A pure substance consists of only one type of substance with uniform properties throughout. In this case, a test tube of zinc oxide would be a pure substance. Zinc oxide (ZnO) is a chemical compound made up of zinc (Zn) and oxygen (O) atoms in a fixed ratio. It has a specific chemical formula and a consistent composition, making it a pure substance.
On the other hand:
B. A container of zinc and oxygen would be a mixture since it contains two different substances, zinc and oxygen, in their elemental forms.
C. A flask of pond water is a mixture because it contains a combination of different substances, such as water, dissolved minerals, microorganisms, and organic matter.
D. A jar of soil is also a mixture since it consists of a combination of various components, including minerals, organic matter, water, air, and possibly microorganisms.
Therefore, the correct answer is A. a test tube of zinc oxide, which represents a pure substance.
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The volume occupied by 454 grams of copper, given a density of 8.92g/mL, can be calculated using the formula for density (Density = Mass / Volume). When rearranged to find volume (Volume = Mass / Density) and substituting the given values, the volume occupied is approximately 50.9 mL.
When calculating volume in chemistry, we use the formula for density, which is: Density = Mass / Volume. In this case, the given values are mass (454g) and density (8.92g/mL). If we rearrange the formula to solve the volume, we get: Volume = Mass / Density. So, if we substitute the given values into the equation, we obtain: Volume = 454g / 8.92g/mL. In performing the operation, we get approximately 50.9 mL. Hence 454 grams of copper occupy 50.9 mL of volume.
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